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enot [183]
3 years ago
15

The longest leg of a right triangle is 12 inches. The hypotenuse is 3 inches longer then twice the shortest leg. How long is the

shortest leg and the hypotenuse of the triangle.
Mathematics
1 answer:
Llana [10]3 years ago
6 0

Answer:

Shortest Leg: 5 inches, Hypotenuse: 13 inches

Step-by-step explanation:

A right triangle follows the pythagorean theorem, a^2+b^2=c^2. C is the hypotenus. A combination found using this is 5, 12, and 13. To double check this, we know that the hypotenus is 2x+3, where x is the smallest leg.

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How might we know whether x is a positive number, negative number, or zero, without solving the equation? 5x = -16.5​
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To be able to get the negative number you have to divide x by a negative number to get your result. Seeing the solution is a negative number but your left side of the equation is a positive number tells us we have to divide by a negative number on the left side and right to give us the solution... (I think)
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I need help with this. What is the answer? (13 x 4 +5²) - 2
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Step-by-step explanation:

7 0
2 years ago
In a study, 42% of adults questioned reported that their health was excellent. A researcher wishes to study the health of people
kobusy [5.1K]

Answer:

The probability that when 11 adults are randomly selected, 3 or fewer are in excellent health is 0.6483.

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of adults questioned reported that their health was excellent.

A random sample of <em>n</em> = 11 adults are selected randomly selected from an area a nuclear power plant.

Of these 11 adults <em>X</em> = 3 reported that their health was excellent.

The proportion of adults who reported that their health was excellent is:

p=\frac{X}{n}=\frac{3}{11}

An adult's health condition is not affected by others, i.e. they are independent.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 11 and <em>p</em> = \frac{3}{11}.

The probability mass function of <em>X</em> is:

P(X=x)={11\choose x}(\frac{3}{11})^{x}(1-\frac{3}{11})^{11-x};\ x=0,1,2,3...

Compute the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health as follows:

P (X ≤ 3) = P (X = 0) + P (X = 1) + P (X = 2) + P (X = 3)

              =\sum\limits^{3}_{x=0}{{11\choose x}(\frac{3}{11})^{x}(1-\frac{3}{11})^{11-x}}\\=0.02998+0.12385+0.23254+0.26197\\=0.64834\\\approx 0.6483

Thus, the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health is 0.6483.

5 0
3 years ago
Given f(x) = 2x + 1, find the range value if the domain value is 1.75.
MAXImum [283]

Given:

The function is

f(x)=2x+1

To find:

The range value if the domain value is 1.75.

Solution:

Domain is the set of input values and range is the set of output values.

Here, range value if the domain value is 1.75. It means the value of function f(x) at x=1.75.

Substitute x=1.75 in the given function.

f(1.75)=2(1.75)+1

f(1.75)=3.5+1

f(1.75)=4.5

Therefore, the required range value is 4.5.

4 0
3 years ago
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