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2 years ago

The claim is the farther the ball drops the higher it will bounce. What are the reasonings and evidence

Chemistry

1 answer:

lions [1.4K]2 years ago

5 0

Answer:

Hey,

As the ball falls, it gains gravitational kinetic energy or GKE, all that means is that it starts to move faster as it falls, As it does so it gains more and more energy so that when it falls it will bounce realy high, it can't destribute all that energy in 1 hit, for such a task you would need a cannon ball.

<em><u>Wbob1314</u></em>

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The thin outer layer of Earth, called the crust, contains only 0.50 percent of Earth's total mass and yet is the source of almos

Rzqust [24]

Answer:

The mass of silicon in kilograms in Earth's crust is $7.2729\times 10^{21} kg$ .

Explanation:

Mass of Earth = $5.9\times 10^{21} tons$

(1 ton= 2000 lb)

(1 lb =453.6 g)

1 ton = 2000 × 453.6 g =907,200 g

Mass of Earth = $5.9\times 10^{21}\times 907,200 g=5.3524\times 10^{27} g$

Percentage of earth crust = 0.50%

Mass of earth crust = M

$0.50\%=\frac{M}{5.3524\times 10^{27}}\times 100$

$M=2.6762\times 10^{25} g$

Percentage of the silicon in Earth's crust = 27.2 %

Mass of silicon in in Earth's crust = m

$Si\%=\frac{m}{M}\times 100$

$27.2\%=\frac{m}{2.6762\times 10^{25} g}\times 100$

$m = 7.2792\times 10^{24} g=7.2729\times 10^{21} kg$

1000 g = 1 kg

The mass of silicon in kilograms in Earth's crust is $7.2729\times 10^{21} kg$ .

7 0

3 years ago

How many moles are in 442.8 g of strontium carbonate (SrCO3)?

GuDViN [60]

Answer:

3 moles

Explanation:

SrCO3

Mass = 442.8g

Molar mass = (87.6 + 12 * [16*3]) = 147.6g/mol

Number of moles = mass / molar mass

Number of moles = 442.8 / 147.6

Number of moles = 3

7 0

3 years ago

Can someone help me with this question?

Softa [21]

Answer:

5 , I think. sorry if its wrong

8 0

3 years ago

The molecular weight of a gas that has a density of 5.75 g/l at stp is __________ g/mol.

Ira Lisetskai [31]

Answer : The molecular weight of a gas is, 128.9 g/mole

Explanation : Given,

Density of a gas = 5.75 g/L

First we have to calculate the moles of gas.

At STP,

As, 22.4 liter volume of gas present in 1 mole of gas

So, 1 liter volume of gas present in $\frac{1}{22.4}=0.0446$ mole of gas

Now we have to calculate the molecular weight of a gas.

Formula used :

$\text{Moles of gas}=\frac{\text{Mass of a gas}}{\text{Molecular weight of a gas}}$

Now put all the given values in this formula, we get the molecular weight of a gas.

$0.0446mole=\frac{5.75g}{\text{Molecular weight of a gas}}$

$\text{Molecular weight of a gas}=128.9g/mole$

Therefore, the molecular weight of a gas is, 128.9 g/mole

8 0

3 years ago

Read 2 more answers

Suppose a student started with 142.0 mg of trans-cinnamic acid, 412 mg of pyridinium tribromide, and 2.30 mL of glacial acetic a

nirvana33 [79]

Answer: Theoretical Yield = 0.2952 g

Percentage Yield = 75.3%

Explanation:

Calculation of limiting reactant:

n-trans-cinnamic acid moles = (142mg/1000) / 148.16 = 9.584*10⁻⁴ mol

pyridium tribromide moles = (412mg/1000) / 319.82= 1.288*10⁻³ mol

n-trans-cinnamic acid is the limiting reactant

The molar ratio according to the equation mentioned is equals to 1:1

The brominated product moles is also = 9.584*10⁻⁴ mol

Theoretical yield = (9.584*10⁻⁴ mol) * (Mr of brominated product)

= (9.584*10⁻⁴ mol) * (307.97) = 0.2952 g

Percentage Yield is : Actual Yield / Theoretical Yield = 0.2223/0.2952

= 75.3%

4 0

3 years ago