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IgorC [24]
3 years ago
9

Find the value of Z^ when z =0.5

Mathematics
1 answer:
LiRa [457]3 years ago
3 0

Step-by-step explanation:

may be this is a answer......

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Increase- From 20 miles to 11 miles
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HshahahahauAiajwhwbahah
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3 years ago
Find a solution to the inequality x &gt; 4.<br> A. 8<br> B. 3<br> C. 4<br> D. 0
ella [17]

Answer:

8

Step-by-step explanation:

Isn't it simple because all other numbers are less than 4?

3 0
2 years ago
As with simple linear regression, we desire the residuals to (select all that apply) have large variance. have constant variance
dimulka [17.4K]

As with simple linear regression, we desire the residuals to:

  • Have constant variance.
  • Have a mean close to 0.

<h3>What is a simple linear regression?</h3>

It should be noted that a simple linear regression simply means a model that describes the relationship between a dependent variable and an independent variable.

In this case, as with simple linear regression, we desire the residuals to have constant variance and have a mean close to 0.

Learn more about regression on:

brainly.com/question/25987747

5 0
2 years ago
Solve the following system by any method -8x-8y=0 -8x+2y=-20
iVinArrow [24]
                     \fbox{Solution by using Matrix} 

\text{Linear Equation} = -8x-8y=0 , -8x+2y=-20

\text{Rewrite the linear equations above as a matrix} 

\left[\begin{array}{ccc}8&-8&0\\-8&2&-20\\\end{array}\right] 

\text{Apply to Row2 : Row2 + Row1} 

\left[\begin{array}{ccc}8&-8&0\\-8&-6&-20\\\end{array}\right] 

\text{ Simplify rows} 

\left[\begin{array}{ccc}8&-8&0\\0&1&10/3\\\end{array}\right] 

\text{Note: The matrix is now in echelon form.}\text{The steps below are for back substitution.} 

\text{Apply to Row1 : Row1 + 8 Row2} 

\left[\begin{array}{ccc}8&0&80/30\\0&1&10/3\\\end{array}\right] 

\text{ Simplify rows}  

\left[\begin{array}{ccc}1&0&10/3\\0&1&10/3\\\end{array}\right] 

\text{Therefore, the solution is} 

x= \dfrac{10}{3} \ \text{and} \ \ y=\dfrac{10}{3}
7 0
3 years ago
Area of regular polygons
Finger [1]
Hello!

To find the area of a hexagon you do 3\frac{3 \sqrt{3} }{2} } a^{2} where a is one of the sides

Since the perimeter is 60 we can do 60/ the sides of the shape

60/6 = 10

So one side is equal to 10

you put that into the formula to get the area of a hexagon and you get 259.81

Hope this helps!
8 0
3 years ago
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