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3 years ago

In which phase(s) do the molecules take the shape of the container?

Chemistry

2 answers:

Katen [24]3 years ago

6 0

Answer:

Liquid and gas

Explanation:

Liquid and gas are the phases of matter that take the shape of container.

This is very simple to imagine, if we have a piece of rock and we put it in a container, it will not take the shape of container as it already has a definite shape and volume. Liquid when put in a container takes the shape of container but varies in volume as per the container.

However, the gas phases is the phase of matter that perfectly takes the shape of container and occupies all the volume of container as well.

If we recall Dalton's Law of Partial Pressures we can see that the pressure exerted by the gas components in a container is same like the pressure exerted by the gas alone. These partial pressures of the component of gas combine in such a way that they exert total pressure equal to the constituents' pressure on the container. This way gases occupy all the volume of a container and take the shape of a container they're placed in.

Hope it help!

strojnjashka [21]3 years ago

5 0

In the liquid and gas phase molecules take the shape of the container.

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A 200.-milliliter sample of CO2(g) is placed in a sealed, rigid cylinder with a movable piston at 296 K and 101.3 kPa. Determine

bagirrra123 [75]

Answer:

The final volume of the sample of gas $V_{2}$ = 0.000151 $m^{3}$

Explanation:

Initial volume $V_{1}$ = 200 ml = 0.0002 $m^{3}$

Initial temperature $T_{1}$ = 296 K

Initial pressure $P_{1}$ = 101.3 K pa

Final temperature $T_{2}$ = 336 K

Final pressure $P_{2}$ = K pa

Relation between P , V & T is given by

$P_{1} \frac{V_{1} }{T_{1} } = P_{2} \frac{V_{2} }{T_{2} }$

Put all the values in the above equation we get

$101.3 (\frac{0.0002}{296} )= 152 (\frac{V_{2} }{336} )$

$V_{2}$ = 0.000151 $m^{3}$

This is the final volume of the sample of gas.

4 0

3 years ago

Solid calcium carbonate (CaCO3) reacts with hydrochloric acid (HCI) to form carbon dioxide, water, and

Pavlova-9 [17]

Using a more concentrated HCl solution and Crushing the CaCO₃ into a fine powder makes the reaction to occur at a faster rate.

<u>Explanation:</u>

CaCO₃(s) + 2HCl(aq) → CaCl₂(aq) + H₂O(aq) + CO₂(g)

When calcium carbonate reacts with hydrochloric acid, it gives out carbon-dioxide in the form of bubbles and there is a formation of calcium chloride in aqueous medium.

The rate of the reaction can be increased by

Using a more concentrated HCl solution

Crushing the CaCO₃ into a fine powder

When concentrated acid is used instead of dilute acid then the reaction will occur at a faster rate.

When CaCO₃ is crushed into a fine powder then the surface area will increases thereby increasing the rate of the reaction.

3 0

2 years ago

Read 2 more answers

Write the name and formulas of the products that would form when hydrochloric acid, HCl, and sodium hydroxide, NaOH, react.

OverLord2011 [107]

The correct answer is sodium chloride. NaCl. Also known as table salt.
I hope this helps you.

6 0

2 years ago

Carbonic anhydrase of erythrocytes (Mr 30,000) has one of the highest turnover numbers known. It catalyzes the reversible hydrat

Afina-wow [57]

Explanation:

According to the given data, the turnover number can be calculated as follows.

Turnover number = $K_{cat} = \frac{V_{max}}{\text{Concentration of enzyme}}$

$V_{max} = \frac{\text{Moles of CO_{2} hydrolyzed}{second}$

Therefore, moles of $CO_{2}$ hydrolyzed is as follows.

Moles of $CO_{2}$ hydrolyzed = $\frac{Mass of CO_{2}}{Molar mass of CO_{2}}$

= $\frac{0.30}{44}$

= 0.00682 moles

Now, moles of $CO_{2}$ hydolyzed per second is calculated as follows.

Moles of $CO_{2}$ hydolyzed per second = $\frac{0.00682}{60}$

= $1.137 \times 10^{-4} moles/second = V_{max}$

And,

Moles of enzyme = $\frac{Mass}{\text{Molar mass}}$

= $\frac{10.0 \mu g}{30000}$

= $3.33 \times 10^{-10}$ moles

Therefore, the value of $K_{cat}$ is as follows.

$K_{cat} = \frac{1.137 \times 10^{-4} moles}{3.333 \times 10^{-10} moles}$

= $0.3411 \times 10^{6}$ per second

= $0.3411 \times 60 \times 10^{6}$ per minute

= $20.466 \times 10^{6}$ per minute

Thus, we can conclude that the turnover number ( $K_{cat}$ ) of carbonic anhydrase (in units of $min^{-1}$ ) is $20.466 \times 10^{6}$ per minute.

6 0

3 years ago

Please help me with my chemistry hw plzzzzz answer my qhestions

tino4ka555 [31]

For 6, celsius to kelvin is simply adding 273.15
So, 297+273.15 = 570.15 kelvin

4 0

3 years ago