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anzhelika [568]
3 years ago
12

Enter an equation that can be used to find x. (Picture below)

Mathematics
1 answer:
Levart [38]3 years ago
3 0

(2x+1)+89=180.  180 is the angle of a straight line.  Set your two known sides equal to 180 and solve for x if needed.

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How much heat in kJ is released when nitrogen and hydrogen react as below to form 100.g ammonia heat equals-92.2kj
tresset_1 [31]

100g of ammonia releases 271.18 kJ of heat.

<u>Explanation:</u>

Given:

N₂ reacts with H₂

The reaction is:

2N₂ + 3H₂ → 2NH₃ + 92.2 kJ

According to the balanced reaction:

2 X 17g of ammonia releases 92.2 kJ of heat

34g of ammonia releases 92.2 kJ of heat

100g of ammonia will release = \frac{92.2}{34} X 100 kJ of heat

                                                 = 271.18 kJ

Therefore, 100g of ammonia releases 271.18 kJ of heat.

8 0
3 years ago
How do you solve f(x) = x2 + x - 20?​
Darina [25.2K]

\huge \bf༆ Answer ༄

Let's solve ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: {x}^{2}  + x - 20

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: {x}^{2}  + 5x - 4x - 20

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x(x + 5) - 4(x + 5)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:(x + 5)(x -  4)

It's factorized now ~ And if you want to find the zeros then equate the expression with 0.

And you will get ;

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x =  - 5 \:  \: and \:  \: 4

4 0
2 years ago
-2x -4 &lt; 10 solve for x
algol [13]

Answer:

the and is x>-7

Step-by-step explanation:

collect like time

-2x<10+4

-2x<14

x>14/-2

x>-7

7 0
3 years ago
Please help me out!!!!!
Neko [114]

Given:

The zeros of the polynomial are -2,\pm 5,4.

Degree = 4

Leading coefficient  = 1

To find:

The polynomial.

Solution:

If c is a zero of a polynomial, then (x-c) must be a factor of the polynomial.

Here, -2,4,-5, 5, are zeros of the required polynomial, so (x+2), (x-4), (x+5), (x-5) are factors of required polynomial.

p(x)=(x+2)(x-4)(x+5)(x-5)

p(x)=(x^2-4x+2x-8)(x^2-5^2)     [\because a^2-b^2=(a-b)(a+b)]

p(x)=(x^2-2x-8)(x^2-25)

Using distributive property, we get

p(x)=x^2(x^2-25)-2x(x^2-25)-8(x^2-25)

p(x)=x^4-25x^2-2x^3+50x-8x^2+200

On combining like terms, we get

p(x)=x^4-2x^3+(-25x^2-8x^2)+50x+200

p(x)=x^4-2x^3-33x^2+50x+200

Here, the leading coefficient is 1. So, it is the required polynomial.

Therefore, the correct option is E.

3 0
3 years ago
Simplify the expression
SashulF [63]

Answer:

The simplified form of given expression\frac{15xy}{5x^{\frac{1}{2}}y^2} is \frac{3x^{\frac{1}{2}}}{y}

Step-by-step explanation:

Given: Expression \frac{15xy}{5x^{\frac{1}{2}}y^2}

We have to write the given expression in simplified form,

Consider the given expression \frac{15xy}{5x^{\frac{1}{2}}y^2}

Divide the numbers \frac{15}{5}=3

we get,

=\frac{3xy}{y^2x^{\frac{1}{2}}}

Apply exponent rule , \frac{x^a}{x^b}\:=\:x^{a-b}

\frac{x}{x^{\frac{1}{2}}}=x^{1-\frac{1}{2}}=x^{\frac{1}{2}}

we get,

=\frac{3yx^{\frac{1}{2}}}{y^2}

Cancel y term, we have,

=\frac{3x^{\frac{1}{2}}}{y}

Thus, The simplified form of given expression\frac{15xy}{5x^{\frac{1}{2}}y^2} is \frac{3x^{\frac{1}{2}}}{y}

4 0
3 years ago
Read 2 more answers
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