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wel
3 years ago
14

HELP ME PLEASE !!! I.D.K WHAT TO DO :((( Will mark brainliest please !!

Chemistry
2 answers:
Svetradugi [14.3K]3 years ago
7 0
I’m sorry but where’s the worksheet lol......
densk [106]3 years ago
7 0

Answer:

bri me jose my new account

Explanation:

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When 4.5 mol al react with 11.5 mol hcl, what is the limiting reactant, and how many moles of h2 can be formed?
ahrayia [7]
1°/ . 2 Al + 6 HCl → 2 AlCl3 + 3 H2 

<span>k1 = n(Al) / 2 = 4,5 / 2 = 2,25 </span>
<span>k2 = n(HCl) / 6 = 11,5 / 6= 1,92 </span>

<span>k2 < k1 ==> HCl is the limiting reactant </span>

<span>6 mol of HCl ---> 2 mol of H2 </span>
<span>11,5 mol of HCl ---> 3,83 mol of H2 </span>
5 0
3 years ago
Any time an atom transfers or shares an electron a is formed
polet [3.4K]
Anytime an atom shares or transfers electrons a bond is formed, sharing= covalent and transfer= ionic
6 0
3 years ago
the enthalpy of vaporization of an roganic alchol is 35.3 kJ/mol at the boiling pointof 64.2 C calculate the entropy change for
bonufazy [111]

Answer:

Explanation:

s=h/t

=35.3/64.2(c)

=35.3/337.2(k)

=0.104

3 0
2 years ago
The following choices contain densities of various materials. Based on these data, which will yield the fastest seismic velocity
Eduardwww [97]

Answer:

D. 5.6 g/cm^3

Explanation:

On the average seismic velocity increases with increase in depth due higher the pressure and more compaction

sand and shales in the Niger Delta Basin density–velocity relationship is

P = 0.31×V^0.25

A derivation of the original Gardner equation to calculate the average densities for sands and shales in wells.

ρ = α ×V^β

where

ρ = bulk density in g/cm3,

V = P-wave velocity,

α = 0.31 for V (m/s) and 0.23 for V(ft/s) and

β = 0.25.

Such that

ρ = 0.31 ×V^0.25

So the fastest seismic velocity will be in the densest material which is D. 5.6 g/cm3

5 0
3 years ago
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mars1129 [50]
From the equation q=mCΔT, set the q of copper = to q of water,

So --- mCΔT(copper)=mCΔT(water).

mass (Cu - copper) = 38g
mass (H2O - water) = 15g
C (H2O) = 4.184 J/g*C
ΔΤ (H2O) = 33-22 = 11*C
ΔΤ (Cu) = 33-80 = -47*C (the final temp is the same for both materials - thermal equilibrium)
C (Cu) = ?

So --- 38(-47)C[Cu]=15(4.184)(11)
     --- C[Cu]=690.36/(-1786) = 0.3865 J/g*C, or 0.39 in 2 sig figs. (The negative goes away, because specific heats are usually positive)
5 0
3 years ago
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