Z varies inversely as w ⇒ z*w=k
when z=7 and w=8 ⇒ 7*8=56=k
when w=14 ⇒ z*14=56
⇒z=56/14
⇒ z=4
Answer: It's C f"(x)= 15x^2+235 Hope that helps!
Step-by-step explanation:
Find the Greatest Common Factor (GCF).
GCF = 5
2. Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)
5(15x^2/5+235/5)
3. Simplify each term in parentheses and that would give you 5(3x^2+47) and that's why I think it C but i'm not so sure but if you get it right can you please make me Brainliest bye and I hope you get it right!
Answer:
(a) Y = 129.3x (b) It is an estimate as it may not be a true reflection of a student's height
Step-by-step explanation:
(a) Estimate of the mean height is the sum of the heights of all the students divided by the total number of students.
The question however needs more information for its estimation as 129.3cm is representative and may be the mean height but it was not stated.
However, assuming it is the mean height,
Let the total number of students be x
while Y is the sum of all individual student heights
Mathematically, mean = Y/x
Therefore 129.3 = Y/ x
implying that Y = 129.3x
(b) It is an estimate because computation of the mean gives an average which may not be an exact value. For example, the mean here is 129.3 whereas there will be many heights greater than that and some lesser than that and obviously, there may be no student with height of 129.3 hence it is an estimate.
Answer:
area: A = 8 m^2
Step-by-step explanation:
Area of a rectangle: A = ab
Answer: Approximately 30.4 degrees
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Work Shown:
324 - 1.6 = 322.4 is the height of the right triangle. This is the opposite side compared to the angle theta.
The adjacent side is 550 since it is the leg closest to the angle theta.
We'll use the tangent rule to connect the two sides
tan(angle) = opposite/adjacent
tan(theta) = 322.4/550
theta = arctan(322.4/550)
theta = 30.3780566013696
theta = 30.4
Your teacher didn't provide any rounding instructions, but I rounded to one decimal place since the value 1.6 is to one decimal place.
