<h2>
Answer:</h2>
<em><u>Angle = 9.965° South of West.</u></em>
<h2>
Explanation:</h2>
In the question,
The speed of the Plane w.r.t to Wind = 256 m/s
Speed of the Wind w.r.t to Ground = 44.3 m/s
Direction of Wind = North from South
Direction Plane wishes to go = West
So,
Using the vectors,
<u>Speed of Wind w.r.t Ground</u> is given by,
<u>Resultant speed of Plane w.r.t Ground</u> is given by,
So,
From the <u>Vector's Triangle Sum property,</u>
<em><u>Therefore, the plane has to move in the direction of 'III quadrant' or 'South-West' direction.</u></em>
Now,
In the triangle, using <u>Pythagoras Theorem</u>,
The speed of the plane = 252.13 m/s
Now,
<u>Therefore, the angle at which the plane should fly to go West is</u><em><u> = 9.965° South of West.</u></em>