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maria [59]
3 years ago
5

Which statement is true? The speed of sound in air is inversely proportional to the temperature of the air. The speed of sound i

n air is directly proportional to the temperature of the air. The speed of sound in air is twice the temperature of the air. The speed of sound in air is not affected by the temperature of the air.
Physics
2 answers:
Ganezh [65]3 years ago
7 0

Answer:

the speed of sound in air is directly proportional to the temperature of the air

Explanation:

sasho [114]3 years ago
6 0
<span> the speed of sound in air is directly proportional to the temperature of the air. The speed of sound depends on the temperature of the surrounding air, this can be represented by a speed of sound in air formula: v = 331m/s + 0.6m/s/C * T (where T is temperature)</span>
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I need help can you help me with this question what is an introduction in replay in sports
GenaCL600 [577]

Answer:

During the live television transmission of sports events, instant replay is often used to show again a passage of play which was especially important or remarkable, or which was unclear at first viewing.

Explanation:

Instant replay or action replay is a video reproduction of something that recently occurred which was both shot and broadcast live. The video, having already been shown live, is replayed in order for viewers to see again and analyze what had just taken place. Some sports allow officiating calls to be overturned after the review of a play. Instant replay is most commonly used in sports, but is also used in other fields of live TV. While the first near-instant replay system was developed and used in Canada, the first instant replay was developed and deployed in the United States.

Outside of live action sports, instant replay is used to cover large pageants or processions involving major dignitaries (e.g. monarchs, religious leaders such as the Catholic Pope, revolutionary leaders with mass appeal), political debate, legal proceedings (e.g. O.J. Simpson murder case), royal weddings, red carpet events at major award ceremonies (e.g. the Oscars), grandiose opening ceremonies (e.g. 2022 Winter Olympics opening ceremony), or live feeds to acts of terrorism currently in progress. Instant replay is used because the events are too large to cover from a single camera angle, events are too fast moving to catch all the nuance on the first viewing, the high points of the event are surrounded by much of a muchness, or punditry is supplied to punch the event up, such as analyzing the daring plunge of a plunging neckline to the last revealing millimeter.

In media studies, the timing and length of the replay clips as well as the selection of camera angles is a form of editorial content with a large impact on how the audience perceives the events covered.

8 0
3 years ago
A 62.0-kg skier is moving at 6.30 m/s on a frictionless, horizontal, snow-covered plateau when she encounters a rough patch 4.90
Klio2033 [76]
Here are the missing questions:
(a) How fast is the skier moving when she gets to the bottom of the hill?
(b) How much internal energy was generated in crossing the rough patch?
Part A
The initial kinetic energy of the skier is:
E_{k0}=m\frac{v_0^2}{2}
Part of this energy is then used to do work against the force of friction. Force of friction on the horizontal surface can be calculated using following formula:
F_f=mg\mu
The work is simply the force times the length:
W_f=F_f\cdot L=mg\mu L
So when the skier passes over the rough patch its energy is:
E=E_{k0}-W_f
When the skier is going down the skill gravitational potential energy is transformed into the kinetic energy:
E_p=E_{k1}\\ mgh=E_{k1}
So the final energy of the skier is:
E_f=E_{k0}-W_f+E_{k1}\\ E_f=m\frac{v_0^2}{2}-mg\mu L+mgh=1856.86$J
This energy is the kinetic energy of the skier:
E_f=m\frac{v_f^2}{2}\\ v_f=\sqrt{\frac{2E_f}{m}}=7.74\frac{m}{s}
Part B
We know that skier lost some of its kinetic energy when crossing over the rough patch. This energy is equal to the work done by the skier against the force of friction.
E_{int}=W_f\\&#10;E_{int}=mg\mu L=894.1$J

4 0
4 years ago
Two concentric current loops lie in the same plane. The outer loop has twice the diameter of the inner loop. The inner loop carr
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Explanation: Please see the attachments below

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3 years ago
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Where are the answer from the choices ?
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aniked [119]

Answer:

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Explanation:

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