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dlinn [17]
3 years ago
7

How are you can’t do that I want no which answer

Mathematics
1 answer:
Sav [38]3 years ago
6 0

The area of the square is 14*14 = 168 ft^2.

The area of the circle is πr^2. The radius is diameter/2 = 7. The area of the circle is 3.14*(7)^2 = 3.14*49 = 153.86 ft^2.

The area of the shaded part is the area of the square minus the area of the circle = 168 - 153.86 = 14.14 ft^2.

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If y varies directly as x and k = 8, find x when y = 8<br><br> 1. 1<br> 2. 8<br> 3. 64
aksik [14]

y = kx so x = y/k

if y = 8 and k = 8 then

x = 8/8 = 1

answer

1. 1

8 0
3 years ago
PLEASE I NEED IT NOW.....In order to solve for the variable in the equation 1-(x+2)+2x = 5(2x-5) - X, Mikel first applies the di
loris [4]

Answer:

1 -x -2 +2x = 10x -25 -x

Step-by-step explanation:

1-(x+2)+2x = 5(2x-5) - X,

Distribute

1 -x -2 +2x = 10x -25 -x

3 0
4 years ago
Which expression can be used to convert 100 USD to Japanese?
Montano1993 [528]

Answer:The expression that can be used to convert 100 USD to Japanese Yen is 100 USD = 100/Y Japanese Yen.

Step-by-step explanation:

3 0
3 years ago
The mean age of 11 women in an office is 31 years old.
BlackZzzverrR [31]

Answer: 30.2

Explanation:

The mean is calculated by taking the sum of the values and dividing by the count.

For instance, for the 6 women, with the mean being 31, we can see that the ages summed to 186:

186

6

=

31

And we can do the same for the men:

116

4

=

29

And now we can combine the sum and count of the men and women to find the mean for the office:

186

+

116

10

=

302

10

=

30.2

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
First change to standard form of first order linear differential equation and then by finding the appropriate integrating factor
Leokris [45]

Answer:

Step-by-step explanation:

Given is a Differential equation as

xy' + y = lnx ; y(e)=1

To bring it to linear form we can divide the full equation by x

y'+\frac{y}{x} =\frac{ln x}{x}

This is of the form

y'+p(x) *y = q(x)

p(x) = 1/x

So find

e^{\int\limits{\frac{1}{x} } \, dx } = e^{ln x} = x

Solution is

xy = \int  {x*lnx /x } \, dx =xln x -x +C

Use the initial value as y(e) =1

e= eln e -e+C\\C=e

So solution is

xy =xln x -x+e

5 0
3 years ago
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