Melting point: 1,502.6 degrees Fahrenheit (817 degrees Celsius)Boiling point: 1,117.4 F (603 C)Number of isotopes (atoms of the same element with a different number of neutrons): 33; 23 whose half-lives are known
Atoms that have lost or gained one or more electrons are called ions.
Answer:
Q = 2640.96 J
Explanation:
Given data:
Mass of He gas = 10.7 g
Initial temperature = 22.1°C
Final temperature = 39.4°C
Heat absorbed = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree. Specific heat capacity of He is 14.267 J/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 39.4°C - 22.1°C
ΔT = 17.3°C
Q = 10.7 g× 14.267 J/g.°C × 17.3°C
Q = 2640.96 J
It would be D. A and B are physical properties