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lapo4ka [179]
3 years ago
6

Find the force on an object which has a mass of 20 kg and an acceleration of 10 m/s2.

Physics
1 answer:
Ilya [14]3 years ago
3 0

Answer:

200N

Explanation:

mass = 20 kg

acceleration = 10 m/s^2

Force = mass * acceleration

         = 20 *10

         = 200 N

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A 5 kg block is sliding down a plane inclined at 30^0 with a constant velocity of 4 m/s. To determine the coefficient of frictio
Leya [2.2K]

Answer:

The necessary information is if the forces acting on the block are in equilibrium

The coefficient of friction is 0.577

Explanation:

Where the forces acting on the object are in equilibrium, we have;

At constant velocity, the net force acting on the particle = 0

However, the frictional force is then given as

F = mg sinθ

Where:

m = Mass of the block

g = Acceleration due to gravity and

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F = 5×9.81×sin 30 = 24.525 N

Therefore, the coefficient of friction is given as

24.525 N = μ×m×g × cos θ = μ × 5 × 9.81 × cos 30 = μ × 42.479

μ × 42.479 N= 24.525 N

∴ μ = 24.525 N ÷ 42.479 N = 0.577

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4 years ago
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The burner on a stove is 325° f. given that the burner emits electromagnetic radiation as a blackbody, what is the maximum wavel
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To solve this, we use the Wien's Displacement Law as shown in the attached picture. First, convert the temperature to Kelvin. 

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C to K:
K = C + 273
K = 162.78 + 273 = 435.78 K

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5 0
3 years ago
What are some examples of wave refractions?​
ankoles [38]

-- The lenses of eyeglasses work because of refraction.

-- A pencil standing in a half-glass of water looks broken because of refraction.

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-- When the sun is setting and it looks squashed ... shorter and wider than a true circle ... that's caused by refraction of the sunlight through Earth's atmosphere.

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2. What energy source produces most of the electrical energy in the United States?
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Answer:

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Explanation:

Approx:

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6 0
2 years ago
A 4.2 kg sled is being pulled along a snow-covered road with a rope that exerts a horizontal force of 6.0 n and, at that moment,
Stella [2.4K]
<span>the body is moving horizontally, it doesnt matter watever kind of horizontal forces are acting.
 Therefore the normal force is equal to the weight
 N=mg=4.2*9.8=41N
 Note: the other data in the problem have no relevance
 answer
</span> the normal force on the sled is 41N 
6 0
4 years ago
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