Answer:
(I). The angular acceleration and number of revolution are -2.5 rad/s² and 500 rad.
(II). The torque is 84.87 N-m.
Explanation:
Given that,
Initial spinning = 50.0 rad/s
Time = 20.0
Distance = 2.5 m
Mass of pole = 4 kg
Angle = 60°
We need to calculate the angular acceleration
Using formula of angular velocity




The angular acceleration is -2.5 rad/s²
We need to calculate the number of revolution
Using angular equation of motion

Put the value into the formula


The number of revolution is 500 rad.
(II). We need to calculate the torque
Using formula of torque


Put the value into the formula


Hence, (I). The angular acceleration and number of revolution are -2.5 rad/s² and 500 rad.
(II). The torque is 84.87 N-m.