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nexus9112 [7]
3 years ago
6

ASAP describe how energy is transferred in a mechanical wave

Physics
1 answer:
kirill115 [55]3 years ago
8 0
A mechanical wave<span> requires an initial </span>energy<span> input. Once this initial </span>energy<span> is added, the </span>wave<span> travels through the medium until all its </span>energy is transferred<span>. In contrast, electromagnetic </span>waves<span> require no medium, but can still travel through one</span>
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How does the use of renewable sources of energy help to solve the problem of energy
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The use of renewable sources of energy help to solve the problem of energy  crisis is discussed below in details.

Explanation:

Environmental and economic advantages of adopting renewable energy incorporate: Creating energy that originates no greenhouse gas discharges from fossil fuels and decreases some kinds of air pollution. Increasing energy stocks and decreasing dependency on shipped fuels.

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3 years ago
A piece of metal has a weight of 6.5 N when it is in air and 3.0 N when it is submerged into water. What is the buoyant force on
Kamila [148]

Answer:

The buoyant force on the piece of iron is 3.5 newtons.

Explanation:

According to the Archimedes' Principle, the piece of metal experiments a buoyant force equal to the weight of the displaced fluid. By Newton's Laws, we have the following formula:

F_{B} - W_{P}+W_{F} = 0 (1)

Where:

F_{B} - Buoyant force on the piece of iron, in newtons.

W_{P} - Weight of the piece of metal, in newtons.

W_{F} - Weight of the fluid displaced by the piece of metal, in newtons.

F_{B} = W_{P}-W_{F}

If we know that W_{P} = 6.5\,N and W_{F} = 3\,N, then the buoyant force on the piece of iron is:

F_{B} = 6.5\,N - 3\,N

F_{B} = 3.5\,N

The buoyant force on the piece of iron is 3.5 newtons.

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3 years ago
3- The period of the simple pendulum depends on:
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c. Both mass of the bob and the length of the spring.

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3 years ago
In the sport of parasailing, a person is attached to a rope being pulled by a boat while hanging from a parachute-like sail. A r
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Answer:

the weight of the rider is 493.53 N

Explanation:

Given the data in the question and as illustrated in the image below,

Tension T = 1900 N

the rider is moving at a constant speed so the net force in the horizontal direction will be 0

In the horizontal direction

F_{sailcos( 30° ) = Tcos ( 17° )

F_{sail = Tcos( 17° ) / cos( 30° )

F_{sail = 1900cos( 17° ) / cos( 30° )

F_{sail = 2098.07 N

Now, In the vertical direction,

F_{sail sin( 30° ) = W + T sin( 17° )

W = F_{sail sin( 30° ) - T sin( 17° )

W = 2098.07sin( 30° ) - 1900sin( 17° )

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Therefore, the weight of the rider is 493.53 N

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