The radiosity of this surface is 299.95W/m².
<h3>
Calculation :</h3>
Given, € 0.8
Ta=0°C 273K
For opaque body., T = 0
a+ p = 1
€ = a (Kirchoff's Law)
p = (1-E)
Radiosity = leaving energy from the surface
= px 240 +€σT4
= (1-E) × 240 +0.8 x 5.67 x 10-8 (2734)
= (1-0.8) × 240 +0.8 x 5.67 × 10-8 (2734)
= 299.95W/m²
So, now after doing the calculations we can say that the radiosity of the surface was 299.95W/m².
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All you can conclude is that something must be burning with an orange flame.
Actually, the "something" that must be burning is the hydrogen that is produced when the sodium reacts with the water:
2Na + 2H₂O → 2NaOH + H₂ + heat
So much heat is produced that the hydrogen catches fire and some of the sodium evaporates into the flame.
The electrons in the sodium atoms get "excited" in the flame. When they drop back to a lower energy level, they emit energy in the form of an orange-yellow light.
Answer:
true
Explanation:
light travels faster than sound.
B
Relative to the observer, the objected, emitting visible light will appear red in color because the wavelength of light is stretched hence acquiring longer wavelength in the visible electromagnetic spectrum (remember red light has the longest wavelength in the visible light spectrum).
Explanation:
Conversely, if the object was moving towards the observer, it would appear blue in color (blue shift) because the relative wavelength of the visible light would be ‘compressed’ (remember this is always relative to the observer) hence the wavelength would be shorter (and blue light has the shortest wavelength in the visible light spectrum).
Both these phenomenons are classified under Doppler shift effect of waves. It also occurs in our daily lives. When a wailing ambulance approaches you, the pitch of the wailing sounds is higher (relative to you). However, when the ambulance passes you and begins stretching away from you, the pitch of the wailing goes low.
Learn More:
For more on Doppler shift effect check out;
brainly.com/question/3841958
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Answer:
See explanation
Explanation:
Now we have, the graph attached.the stable disintegration product of C-14 is N-14.
Then;
Since the mass of C-14 originally present is 64g, at a time t= 17100 years, we will have;
N/No = (1/2)^t/t1/2
N = mass of C-14 at time t
No= mass C-14 originally present
t = time taken for N amount of C-14 to remain
No = mass of C-14 originally present
t1/2 = half life of C-14
N/64 = (1/2)^17,100/5730
N/64 = (1/2)^3
N/64 = 1/8
8N = 64
N = 8 g
