Ask question

Ask question

All categories

3 years ago

5

A lahar is a type of mudflow that occurs

2 answers:

Fittoniya [83]3 years ago

7 0

I'd guess A or D, but my gut says A

victus00 [196]3 years ago

5 0

The answer is C after a volcanic eruption

You might be interested in

The solubility of magnesium phosphate at a given temperature is 0.173 g/L. Calculate the Ksp at this temperature. After you calc

jek_recluse [69]

Answer: $K_{sp}=1.25\times 10^{-14}$

$pK_{sp}=13.90$

Explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as $K_{sp}$

The equation for the ionization of magnesium phosphate is given as:

$Mg_3(PO_4)_2\rightarrow 3Mg^{2+}+2PO_4^{3-}$

When the solubility of $Mg_3(PO_4)_2$ is S moles/liter, then the solubility of $Mg^{2+}$ will be 3S moles\liter and solubility of $PO_4^{3-}$ will be 2S moles/liter.

Thus S = 0.173 g/L or $\frac{0.173g/L}{262.8g/mol}=0.00065mol/L$

$K_{sp}=(3S)^3\times (2S)^2$

$K_{sp}=108S^5$

$K_{sp}=108\times (0.00065)^5=1.25\times 10^{-14}$

$pK_{sp}=-log(K_{sp})=\log (1.25\times 10^{-14})=13.90$

5 0

2 years ago

15. A pipe leaks water at a rate of 1.24 mL/s. What is the rate of the water leak in L/hr?<br> ALL

alex41 [277]

Answer:

4.46

Explanation:

1.24 ml= 0.00124 L

3600 s=1 hr

0.00124 x 3600=4.46

8 0

2 years ago

The electrical charge of the nucleus is determined by:

elixir [45]

I think it’s electron:)

7 0

2 years ago

A resistor is placed in a circuit. The voltage of the circuit is changed and the current is measured. The graph seen here shows

Arturiano [62]

Answer- 2 Ohms

explain- i took the test!

6 0

2 years ago

Calculate: A. Mercury has a specific Heat Capacity of 0.14 J/goC. How much heat is needed to raise the thermometer temperature 1

kari74 [83]

Answer:

$\boxed {\boxed {\sf 56 \ Joules}}$

Explanation:

We are given the mass, specific heat, and temperature, so we must use this formula for heat energy.

$q=mc \Delta T$

The mass is 5 grams, the specific heat capacity is 0.14 Joules per gram degree Celsius. Let's find the change in temperature.

ΔT= final temperature - initial temperature
ΔT= 95°C - 15°C = 80°C

We know the variables and can substitute them into the formula.

$m= 5 \ g \\c= 0.14 \ J/ g \ \textdegree C \\\Delta T= 80 \ \textdegree C$

$q= (5 \ g )( 0.14 \ J/ g \ \textdegree C ) ( 80 \ \textdegree C)$

Multiply the first numbers. The grams will cancel.

$q= 0.7 \ J/ \textdegree C(80 \ \textdegree C )$

Multiply again. This time the degrees Celsius cancel.

$q= 56 \ J$

56 Joules of heat are needed.

4 0

2 years ago