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RoseWind [281]
3 years ago
14

A compound containing phosphorus and oxygen has a molar mass of 157.9 g/mol and an empirical formula of PO3 .

Chemistry
1 answer:
Yuki888 [10]3 years ago
3 0

<u>Answer:</u> The molecular formula of the compound is P_2O_6

<u>Explanation:</u>

The molecular formula is the chemical formula that tells about the number of atoms of each element present in a compound. Molecular formula and empirical formula can also be the same when the number of atoms is in the simplest whole-number ratio.

To calculate the molecular formula, the number of atoms of the empirical formula is multiplied by a factor known as valency that is represented by the symbol, 'n'.

n=\frac{\text{Molecular mass}}{\text{Empirical mass}}        ...(1)

Given empirical formula is PO_3

Empirical mass = [(1\times 30.97) + (3\times 15.99)]=78.94 g/mol

Molecular mass = 157.9 g/mol

Plugging values in equation 1:

n=\frac{157.9 g/mol}{78.94g/mol}\\\\n=2

Molecular formula of the compound becomes P_{2\times 1}O_{2\times 3}=P_2O_6

Hence, the molecular formula of the compound is P_2O_6

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Consider the balanced equation of K I KI reacting with P b ( N O 3 ) 2 Pb(NOX3)X2 to form a precipitate. 2 K I ( a q ) + P b ( N
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Answer: 50.7 grams

Explanation:

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

a) moles of KI

\text{Number of moles}=molarity\times {\text {Volume in L]}=0.417M\times 0.528L=0.220moles

The balanced chemical equation is:

2KI(aq)+Pb(NO_3)_2(aq)\rightarrow PbI_2(s)+2KNO_3(aq)

KI is the limiting reagent as it limits the formation of product and Pb(NO_3)_2 is in excess.

According to stoichiometry :

2 moles of KI give =  1 mole of PbI_2

Thus 0.220 moles of KI give=\frac{1}{2}\times 0.220=0.110moles  of PbI_2

Mass of PbI_2=moles\times {\text {Molar mass}}=0.110moles\times 461.01g/mol=50.7g

Thus 50.7 g of PbI_2 will be formed.

6 0
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How many moles of iron(III) hydroxide precipitate will form when 2.7 moles of aqueous sodium hydroxide reacts completely with ex
aalyn [17]

Answer:

0.9 mole of Fe(OH)3.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

Fe(NO3)3 + 3NaOH —> Fe(OH)3 + 3NaNO3

Now, we can determine the moles of iron (III) hydroxide formed from the reaction as follow:

From the balanced equation above,

3 moles of NaOH reacted to produce 1 mole of Fe(OH)3.

Therefore, 2.7 moles of NaOH will react to produce = 2.7/3 = 0.9 mole of Fe(OH)3.

Therefore, 0.9 mole of Fe(OH)3 is produced from the reaction.

7 0
4 years ago
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