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serious [3.7K]
3 years ago
10

What is occurring during the flat section of the graph below on the red arrow labeled boiling, between liquid and gas? gas (3.)

OO liquid temperature solid time (minutes) O A. Heat is being absorbed, allowing particles of the liquid to overcome the atmospheric pressure. B. Heat is being absorbed, allowing particles of the liquid to overcome the vapor pressure. C. Heat is being released, allowing particles of liquid to overcome the pressure, and is why the temp does not increase. D. The temperature is no longer increasing even though heat is still being added because the heat is being absorbed to lower the melting point​
Chemistry
1 answer:
Aleksandr [31]3 years ago
7 0
Heat is been absorb allowing particles of the liquid to overcome the vapor pressure
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odium carbonate (Na2CO3Na2CO3) is used to neutralize the sulfuric acid spill. How many kilograms of sodium carbonate must be add
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Answer : The mass of sodium carbonate added to neutralize must be, 6.54\times 10^3kg

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First we have to calculate the moles of H_2SO_4.

\text{Moles of }H_2SO_4=\frac{\text{Mass of }H_2SO_4}{\text{Molar mass of }H_2SO_4}

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Conversion used : (1 kg = 1000 g)

Now put all the given values in the above expression, we get:

\text{Moles of }H_2SO_4=\frac{6.05\times 10^6g}{98g/mol}=6.17\times 10^4mol

The moles of H_2SO_4 is, 6.17\times 10^4mol

Now we have to calculate the moles of Na_2CO_3

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Na_2CO_3+H_2SO_4\rightarrow Na_2SO_4+H_2CO_3

From the balanced chemical reaction we conclude that,

As, 1 mole of H_2SO_4 neutralizes 1 mole of Na_2CO_3

So, 6.17\times 10^4mol of H_2SO_4 neutralizes

Now we have to calculate the mass of Na_2CO_3

\text{ Mass of }Na_2CO_3=\text{ Moles of }Na_2CO_3\times \text{ Molar mass of }Na_2CO_3

Molar mass of Na_2CO_3 = 106 g/mole

\text{ Mass of }Na_2CO_3=(6.17\times 10^4mol)\times (106g/mole)=6.54\times 10^6g=6.54\times 10^3kg

Thus, the mass of sodium carbonate added to neutralize must be, 6.54\times 10^3kg

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