The answer is a bc it decreases
To find this you have to find the molar mass of CO2 which you can get on the periodic table, 12 + 16 + 16 = 44 g/mol
4.49 x 10^0 / 44 g/mol = .1020 mol CO2
1 mol = 6.022 x 10^23 molecules (avogadros number)
so .1020 mol x 6.022 x 10^23 =
6.14 x 10 ^22 molecules CO2
Hey there!
Moles of stock solution:
47.0 mL in liters : 47.0 / 1000 => 0.047 L
n = M * V
n = 0.400 * 0.047
n = 0.0188 moles
Volume final :
M = n / V
0.100 = 0.0188 / V
V = 0.0188 / 0.100
V = 0.188 L => 188 mL
Therefore Watter added :
volume final - volume initial
188 mL - 47.0 mL => 141 mL
Hope That helps!
