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jek_recluse [69]
3 years ago
10

What is the difference between fusion and melting?

Chemistry
1 answer:
photoshop1234 [79]3 years ago
4 0
Fusion is joining two or more things together in resulting of the form of one thing
Melting is to make something liquefied by the use of heat
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Reduction occurs at which electrode?
OLEGan [10]

Answer:

The electrode that removes ions from solution

Explanation:

Each electrochemical cell consists of an anode and a cathode. Oxidation occurs at the anode and reduction occurs at the cathode.

At the anode, ions move from the electrode into the solution while at the cathode ions move from the solution to the electrode.

At the cathode, metal ions accept electron(s) and become deposited on the electrode hence this electrode removes ions from solution. This is reduction.

8 0
3 years ago
Helpppp me plzz....
Dmitry_Shevchenko [17]

2.a) warm air is lighter than cold air so thats why it's warmer upstairs than downstairs
3.d) Conduction<span> is the process by which heat energy is transmitted through contact with neighboring molecules</span> 
4.d) the lamp radiates heat throughout the plants 
4 0
3 years ago
Why is the melting point of hydrogen flourine abnormally higher than other halogen acids.​
Tems11 [23]

"The other halogens are not as electronegative and so other hydrogen halides cannot form hydrogen bonds between molecules. Only London Forces are formed. - Therefore more energy is required to break the intermolecular forces in HF than the other hydrogen halides and so it has a higher boiling point."

not a hack link, just stating where i got your answer from! -

https://www.mytutor.co.uk/answers/17558/A-Level/Chemistry/Explain-the-unusually-high-boiling-point-of-HF/

8 0
2 years ago
Lt takes 4 hr 39 min for a 2.00-mg sample of radium-230 to decay to 0.25 mg. what is the half-life of radium-230?
Rufina [12.5K]
Radioactive decay => C = Co { e ^ (- kt) |

Data:

Co = 2.00 mg
C = 0.25 mg
t = 4 hr 39 min

Time conversion: 4 hr 39 min = 4.65 hr

1) Replace the data in the equation to find k

C = Co { e ^ (-kt) } => C / Co = e ^ (-kt) => -kt = ln { C / Co} => kt = ln {Co / C}

=> k = ln {Co / C} / t =  ln {2.00mg / 0.25mg} / 4.65 hr = 0.44719

2) Use C / Co  = 1/2 to find the hallf-life

C / Co = e ^ (-kt) => -kt = ln (C / Co)

=> -kt = ln (1/2) => kt = ln(2) => t = ln (2) / k

t = ln(2) / 0.44719 = 1.55 hr.

Answer: 1.55 hr
6 0
3 years ago
Volume and moles are __________ related. This relationship can be calculated by using ___________ Law.
Kryger [21]

Answer:

The correct answer is - directly; Avogadro’s.

Explanation:

At the same temperature and pressure, gases of the same or equal volume have the same number of molecules. The relation between the moles of the gases and the volume of the gases are indirectly proportional to one another at the same temperature and pressure. This law is called Avogadro's law. In the case of an ideal gas of a particular mass has the volume and moles are directly proportional.

Thus, the correct answer is - directly; Avogadro’s.

6 0
3 years ago
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