55.36 is the mass of Calcium Bromide is needed to make 0.500 L of 0.554 M solution.
Explanation:
Data given:
mass of Ca = ?
molarity of the calcium bromide solution = 0.554 M
Volume of the calcium bromide solution= 0.5 L
First the moles of calcium bromide is calculated as:
molarity =
number of moles = 0.554 x 0.5
number of moles = 0.277 moles of calcium bromide
atomic mass of calcium bromide = 199.89 grams/mole
mass = atomic mass x number of moles
mass of calcium bromide = 199.89 x 0.277
= 55.36 grams
mass of calcium bromide required is 55.36 grams to make solution of 0.554 M in a solution of 0.5 litres.
Answer:
1 mol contains 6.02 x 10^23 molecules. So 0.25 mols will contain 0.25 x 6.02 x 10^23 molecules.
Explanation:
i hope this helps!!!
Answer:
2HClO4 + Ca(OH)2 = Ca(ClO4)2 + 2H2O
Explanation:
Formula for aqueous perchloric acid is; HClO_4 (aq)
Formula for aqueous calcium hydroxide is; Ca(OH)_2 (aq)
Thus chemical equation is;
HClO4 + Ca(OH)2 = Ca(ClO4)2 + H2O
We have to balance it and so we now have;
2HClO4 + Ca(OH)2 = Ca(ClO4)2 + 2H2O