Answer:
7.82 g of Cu
Explanation:
2 moles of Al react to 3 moles of copper sulfate in order to produce 3 moles of copper and 1 mol of aluminum sulfate.
Firstly we determine the moles of reactant.
As copper sulfate is in excess, Al is the limiting.
2.75 g . 1mol /26.98g = 0.102 moles
Ratio is 2:3. 2 moles of Al, can produce 3 moles of Cu
So the 0.102 moles of Al will produce(0.102 . 3) /2 = 0.153 moles.
We convert moles to mass: 0.153 mol . 63.5g /mol = 9.71 g
That's the theoretical yield (100 % yield reaction)
We know that: (yield produced / theoretical yield) . 100 = percent yield
We replace:
(Yield produced / 9.71g) . 100 = 80.5 %
(Yield produced / 9.71g) = 0.805
Yield produced = 0.805 . 9.71g = 7.82 g
One of the oxygen atoms in the anion O3− is hypervalent and the formal charge on this oxygen atom is -1.
Ozone is a triatomic molecule. The anion formed from ozone is called the ozonide anion. This anion is also triatomic. The resonance structures of the ozonide anion are shown in the image attached to this answer.
We can see that one of the oxygen atoms in the ozonide ion is hypervalent because it contains ten instead of eight electrons. This hypervalent oxygen atom has a formal charge of -1 while the two other oxygen atoms has a formal charge of zero.
Learn more: brainly.com/question/8646601
Answer:
porous = allowing liquid or air to pass through slowly
I hope it's helpful
1 mol N₂ - 2 mol NH₃
6 mol N₂ - x mol NH₃
x=2×6/1=12 mol
12 mol NH₃
<span>CO(NH2)2 the only product consists of 1 Carbon 1 Oxygen , 2 Nitrogen and 4 Hydrogen We are heating Ammonium Cyanate, Ammonium Ion NH4+ NH4+ consists of 1 Nitrogen 4 Hydrogen. Compare the reactant decomposed and product formed.
There should be 2 Nitrogen so Cyanate must contain one Nitrogen atom, one Carbon and one oxygen.</span>
