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kow [346]
3 years ago
14

Please help me with this science question

Physics
1 answer:
NeX [460]3 years ago
5 0
Heat flows from hotter to colder objects 
metal rod<fire 
hat>snowman
ice cube<warm water
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The impulse given to a ball with massb of 2kg is 16 Ns. if the ball starts grin the rest, what is its final velocity?
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B because it will not be any thing else

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The five factors of production include land, _______, capital, entrepreneurship, and _______.
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3 years ago
The electric field at the surface of a charged, solid, copper sphere with radius 0.220 mm is 4200 N/CN/C, directed toward the ce
NISA [10]

Answer:

The potential at the center of the sphere is -924 V

Explanation:

Given;

radius of the sphere, R = 0.22 m

electric field at the surface of the sphere, E = 4200 N/C

Since the electric field is directed towards the center of the sphere, the charge is negative.

The Potential is the same at every point in the sphere, and it is given as;

V = \frac{1}{4 \pi \epsilon_o} \frac{q}{R} -------equation (1)

The electric field on the sphere is also given as;

E = \frac{1}{4 \pi \epsilon _o} \frac{|q|}{R^2}

|q |=  4 \pi \epsilon _o} R^2E

Substitute in the value of q in equation (1)

V = \frac{1}{4 \pi \epsilon_o} \frac{-(4 \pi \epsilon _o R^2E)}{R} \ \ \ \ q \ is \ negative\ because \ E \ is\ directed  \ toward \ the \ center\\\\V = -RE\\\\V = -(0.22* 4200)\\\\V = -924 \ V

Therefore, the potential at the center of the sphere is -924 V

8 0
3 years ago
What is rickrolling<br><br> ...
Andreyy89

Answer:

"a prank and an Internet meme involving an unexpected appearance of the music video for the 1987 Rick Astley song "Never Gonna Give You Up". The meme is a type of bait and switch using a disguised hyperlink that leads to the music video."

Explanation: G O O G L E

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<span>Answer: KE = (11/2)mω²r², particle B must have mass of 2m, while A has mass m. Then the moment of inertia of the system is I = Σ md² = m*(3r)² + 2m*r² = 11mr² and then KE = ½Iω² = ½ * 11mr² * ω² = 11mr²ω² / 2 So I'll proceed under that assumption. For particle A, translational KEa = ½mv² but v = ω*d = ω*3r, so KEa = ½m(3ωr)² = (9/2)mω²r² For particld B, translational KEb = ½(2m)v² but v = ω*r, so KEb = ½(2m)ω²r² so total translational KE = (9/2 + 2/2)mω²r² = 11mω²r² / 2 which is equal to our rotational KE.</span>
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3 years ago
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