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3 years ago

Same object differs in water than in air?

Physics

1 answer:

Ipatiy [6.2K]3 years ago

8 0

Answer:

Yes

Say that I have a bomb that is triggerded when it is in water. In air the bomb does not change, but in water it blows up.

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What Type of Wave is Shown Below? PLZ ANSWER I'M ALREADY FAILING AT THIS SUBJECT!

uranmaximum [27]

Answer:

A......................

8 0

3 years ago

A lightbulb marked "75 W [at] 120 V" is screwed into a socket at one end of a long extension cord, in which each of the two cond

Vedmedyk [2.9K]

Answer:

Part c)

$P = 73.8 Watt$

Explanation:

Light bulb is marked as 75 W and 120 Volts

so it means that when we apply 120 volts across the bulb then it will consume the total power of 75 W

now when we connected the bulb with the help of conducting wires with some resistance across them then few of its voltage will fall across the wires

due to which the voltage across bulb is less than 120 Volts

So the power given by the bulb is less than 75 W

Part c)

Resistance of the bulb is given as

$R = \frac{V^2}{P}$

$R = \frac{120^2}{75}$

$R = 192 ohm$

now total resistance of the circuit

$R_{net} = 192 + 0.8 + 0.8$

now current in the circuit

$i = \frac{120}{193.6}$

$i = 0.62 A$

so actual power delivered to the bulb is given as

$P = i^2 R$

$P = 0.62^2 \times 192$

$P = 73.8 Watt$

5 0

4 years ago

A force of 8,480 N is applied to a cart to accelerate it at a rate of 26.5 m/s2. What is the mass of the cart?

katrin2010 [14]

Answer:

Just use F =ma where m is mass and a is acc.

8 0

3 years ago

The voltage and power ratings of a particular light bulb, which are its normal operating values, are 110 V and 60 W. Assume the

Alex787 [66]

Answer:

The voltage operating is the 85,20563362

Explanation:

Power is the relation between Voltage and Current so knowing the resistance is going to be constant the equation of power can be just replacing in voltage terms:

1. $P=I*V$

using also Law OHM

2. $V= I*R$

$I = \frac{V}{R}$

Replacing 2 in the equation 1 so all the data are going to be in Voltage terms:

1. $P= \frac{V}{R} *V$

$P= \frac{V^{2} }{R}$ ⇒ $R= \frac{V^{2} }{P}$

$R= \frac{110^{2} v }{60 w}$

$R= 201,6666667$ Ω

So the resistance is constant so the current is going to be the same at the other Power 36 W:

$P= \frac{V^{2} }{R}$

$V^{2} = R*P$

$V=\sqrt{R*P}$

$V=\sqrt{201,6666667*36 }$

$V=\sqrt{7260}$ ⇒ $V= 85,20563362$

6 0

3 years ago

Plastic foam is about 0.10 times as dense as water. What weight of bricks could you stack on a 1m x 1m x 0.10m slab of foam, so

goblinko [34]

Answer: Weight = 98.1N

Explanation:

Density of water = 1000 kg/m^3

Given that the Plastic foam is about 0.10 times as dense as water. That is,

Density of plastic foam = 0.1 × 1000 = 100kg/m^3

The volume V = 1 ×1×0.1 = 0.1 m^3

Density is the ratio of mass to volume

Density = mass/volume

Let us substitute for density and volume to get mass.

100 = M/0.1

Make M the subject of formula

M = 100 × 0.1 = 10 kg

Weight = mg

Where g = 9.81 m/s

Substitute the M and g into the formula

Weight = 10 × 9.81 = 98.1 N

Therefore, the weight of the brick is 98.1 N

4 0

4 years ago