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Reil [10]
3 years ago
8

Same object differs in water than in air?

Physics
1 answer:
Ipatiy [6.2K]3 years ago
8 0

Answer:

Yes

Say that I have a bomb that is triggerded when it is in water. In air the bomb does not change, but in water it blows up.

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1)Pitch is measure of the ____________ of sound.
amid [387]

Answer:

1) wave length

2) parallel reflection

7 0
2 years ago
Which parts of the graph would increase if all of earth's polar ice melts? Which part would decrease?
Sedbober [7]

Answer:

the answer to the question is the part that is reflected by clouds and atmosphere 26%

8 0
3 years ago
Sí un auto viaja a 8m/s determine Tiempo en llegar a 200km de distancia Distancia que recorre en 40 minutos
GrogVix [38]

Answer:

a. Tiempo = 25000 segundos

b. Distancia = 19200 metros

Explanation:

Dados los siguientes datos;

Velocidad = 8 m/s

Distancia = 200 km a metros = 200 * 1000 = 200,000

Para encontrar el tiempo para cubrir la distancia anterior;

Tiempo = distancia/velocidad

Tiempo = 200000/8

Tiempo = 25000 segundos

b. Para encontrar la distancia recorrida en 40 minutos;

Tiempo = 40 minutos a segundos = 40 * 60 = 2400 segundos

Distancia = velocidad * tiempo

Distancia = 8 * 2400

Distancia = 19200 metros

7 0
3 years ago
As shown in the diagram below, a rope attached to a 500.-kilogram crate is used to exert a force of 45 newtons at an angle of 65
kaheart [24]

Answer:

19.01 N

Explanation:

F = Force being applied to the crate = 45 N

\theta = Angle at which the force is being applied = 65^{\circ}

Horizontal component of force is given by

F_x=F\cos\theta\\\Rightarrow F_x=45\times \cos65^{\circ}\\\Rightarrow F_x=19.01\ \text{N}

The horizontal component of the force acting on the crate is 19.01 N.

4 0
3 years ago
A force F with arrow= (5xî+ 4yĵ), where F with arrow is in newtons and x and y are in meters, acts on an object as the object mo
harkovskaia [24]

Answer:

w= 62.75 J

Explanation:

Given that

Force vector F= 5 x i + 4 y j

Space vector or displacement vector d= 5.01 i

We know that work (w)

w=∫ F.ds

w= ∫(5 x i + 4 y j) .dx            ( only object is moving in x- direction)

w=\int_{0}^{5.01}5xi.dxi

w=\int_{0}^{5.01}5x.dx

w=\left [\dfrac{5}{2}x^2\right ]_0^{5.01}

w= 2.5 x 5.01² J

w= 62.75 J

6 0
3 years ago
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