A shotgun of mass 3kg fires a bullet of 0.1kg at a velocity of 250m/s. What is the recoil velocity of the gun

Physics

1 answer:

alisha [4.7K]3 years ago

6 0

Answer:

8.33 m/s

Explanation:

The formula to apply is that of conservation of linear momentum taking that the this case is a single fire non reciprocating action.

Thus,

m₁v₁ = m₂v₂ where;

m₁ = mass of the shotgun = 3kg

v₁ = recoil velocity of the gun

m₂ = mass of bullet

v₂ = velocity of bullet

Substitute values in the equation as;

m₁v₁ = m₂v₂

3*v₁ =0.1*250

3v₁ =25

v₁ =25/3 = 8.33 m/s

<u>The recoil velocity of the gun is 8.33 m/s</u>

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