A shotgun of mass 3kg fires a bullet of 0.1kg at a velocity of 250m/s. What is the recoil velocity of the gun
1 answer:
Answer:
8.33 m/s
Explanation:
The formula to apply is that of conservation of linear momentum taking that the this case is a single fire non reciprocating action.
Thus,
m₁v₁ = m₂v₂ where;
m₁ = mass of the shotgun = 3kg
v₁ = recoil velocity of the gun
m₂ = mass of bullet
v₂ = velocity of bullet
Substitute values in the equation as;
m₁v₁ = m₂v₂
3*v₁ =0.1*250
3v₁ =25
v₁ =25/3 = 8.33 m/s
<u>The recoil velocity of the gun is 8.33 m/s</u>
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