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goldenfox [79]
3 years ago
6

6. What are two uses for nonmetals?

Chemistry
1 answer:
lesantik [10]3 years ago
5 0
Uses of nonmetals in our daily life: Oxygen which is 21% by volume helps in the respiration process.

Nonmetals used in fertilizers: Fertilizers contain nitrogen.

Nonmetals used in crackers: Sulphur and phosphorus are used in fireworks.
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Fill in the blanks to complete the table
aleksandrvk [35]

The atomic number(Z) is equal to the number of protons to equal to number of electrons.

The number of neutrons is equal to atomic mass minus the atomic number

n=A-Z

For Zn^2+, Z=28, e=28

For iron, Z=25,A=55

The number of neutrons is 55-25=30

The charge is zero

For O^2-, Z=8+2=10, n=p=10

The number of neutrons is 16-10=6

For sulfur, Z=16,A=34

For S2-, Z=16+2=18, A=34

The charge is 2-

  • The atomic number is the basis of the periodic table.
  • It is equal to the number of protons.
  • The number of neutrons is atomic mass minus atomic number.

To learn more about atomic number visit:

brainly.com/question/16858932

#SPJ1

3 0
1 year ago
You have a substance with a length of 2 cm, width of 3 cm, and a height of 4 cm. Its density is known to be .5 g/cm3. What is th
otez555 [7]

Explanation:

They are related by the the density triangle.

Explanation:

They are related by the the density triangle.

mcdn1.teacherspayteachers.com

d =

m

V

m = d×V

V =

m

d

DENSITY

Density is defined as mass per unit volume.

d =

m

V

Example:

A brick of salt measuring 10.0 cm x 10.0 cm x 2.00 cm has a mass of 433 g. What is its density?

Step 1: Calculate the volume

V = lwh = 10.0 cm × 10.0 cm × 2.00 cm = 200 cm³

Step 2: Calculate the density

d =

m

V

=

433

g

200

c

m

³

= 2.16 g/cm³

MASS

d =

m

V

We can rearrange this to get the expression for the mass.

m = d×V

Example:

If 500 mL of a liquid has a density of 1.11 g/mL, what is its mass?

m = d×V = 500 mL ×

1.11

g

1

m

L

= 555 g

VOLUME

d =

m

V

We can rearrange this to get the expression for the volume.

V =

m

d

Example:

What is the volume of a bar of gold that has a mass of 14.83 kg. The density of gold is 19.32 g/cm³.

Step 1: Convert kilograms to grams.

14.83 kg ×

1000

g

1

k

g

= 14 830 g

Step 2: Calculate the volume.

V =

m

d

= 14 830 g ×

1

c

m

³

19.32

g

= 767.6 cm³

5 0
2 years ago
Can someone tell me how to draw a atomic model for Cd
tensa zangetsu [6.8K]

Explanation:

there you go you can just look up atomic model for CD and click images

5 0
3 years ago
HOW FAST CAN YOU ANSWER ( new)
GrogVix [38]

Answer:

d

Explanation:

6 0
2 years ago
Read 2 more answers
Which sub-atomic particle is positively charged and found in the nucleus?
Anarel [89]
The proton has a positive charge.
4 0
3 years ago
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