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Gekata [30.6K]
3 years ago
12

Round 0.0011675cg to four significant figures

Chemistry
1 answer:
atroni [7]3 years ago
8 0

Answer:

answer is 0.001168 is correct

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Why do you Think you weight less on Uranus than earth even though it is more massive planet ? 
Phantasy [73]

Answer:

You would weigh less on Uranus than on Earth because Uranus is far less mass-ive and dense than the Earth. This means that there is less gravity. Therefore, you would weigh less.

Explanation:

Even though Uranus is bigger, it is less massive; that is, there is less mass that makes up the planet. The volume of the planet might be larger, but the actual amount of mass isn't.

By the way, you couldn't stand on Uranus. It's made of gas!

7 0
3 years ago
What is the concentration of hydronium ion in a 0.121 M HCl solution?
kogti [31]

Answer:

C) 0.121 M

Explanation:

HCl + H₂O = H₃O⁺ + OH⁻

.121M              .121M

HCl is a strong acid . It will dissociate almost 100 % so the concentration of acid and hydronium ion formed will be equal . It is to be noted that hydronium ion is formed due to association of H⁺ and H₂O . H⁺ is formed due to ionisation of HCl .

So concentrtion of hydronium ion ( H₃O⁺ ) will be .121 M.

7 0
3 years ago
Explain specifically how an electron gives off light in an atom.
exis [7]

Answer:

Then, at some point, these higher energy electrons give up their "extra" energy in the form of a photon of light, and fall back down to their original energy level.

Explanation:

When properly stimulated, electrons in these materials move from a lower level of energy up to a higher level of energy and occupy a different orbital.

3 0
3 years ago
A monoprotic weak acid, HA , dissociates in water according to the reaction HA(aq)↽−−⇀H+(aq)+A−(aq) The equilibrium concentratio
Pachacha [2.7K]

Answer:

pK_{a} of HA is 6.80

Explanation:

pK_{a}=-logK_{a}

Acid dissociation constant (K_{a}) of HA is represented as-

                K_{a}=\frac{[H^{+}][A^{-}]}{[HA]}

Where species inside third bracket represents equilibrium concentrations

Now, plug in all the given equilibrium concentration into above equation-

K_{a}=\frac{(2.00\times 10^{-4})\times (2.00\times 10^{-4})}{0.250}

So, K_{a}=1.6\times 10^{-7}

Hence pK_{a}=-log(1.6\times 10^{-7})=6.80

6 0
3 years ago
HELP a #QUEEN out pls??
Anastaziya [24]

Answer:

what the acctual fhuck typa chinese algorithim is dis, youve got me bamboozled frffr

Explanation:

jk jk.........

__5___SiO2 + ___2___CaC2 → __5___Si + ____2___CaO + __4___CO2

4 0
3 years ago
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