<span>200 moles
The balanced equation for creating water from hydrogen and oxygen gas is
2H2 + O2 => 2H2O
So for every mole of oxygen gas, you need two moles of hydrogen. So looking that the amount of oxygen and hydrogen you have, it's obvious that oxygen is the limiting reactant since 100 moles of oxygen will consume 200 moles of hydrogen. While 210 moles of hydrogen requires 105 moles of oxygen.
Now for each mole of oxygen gas you use, you create 2 moles of water. So
100 mol * 2 = 200 mol
So you can create 200 moles of water from the given amounts of reactants.</span>
The answer is 6.58mL or 0.00658L. How I got this answer step by step is included in the photo below. Hope this helps!
Answer:
option D
Explanation:
Given,
V₁ = 285 L
P₁ = 530 mm Hg
Standard pressure
P₂ = 760 mm Hg
V₂ = ?
Using relation between pressure and volume



Hence, volume of the propane at standard pressure is equal to 198.8 L.
Hence, the correct answer is option D.
Answer:
B
Explanation:
I had this question and got it right