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serg [7]
3 years ago
13

Calculate the formula mass of calcium iodate, ca(io3)2, in atomic mass units (amu or u).

Chemistry
1 answer:
VARVARA [1.3K]3 years ago
7 0
<span>389.88094 amu First we look up the atomic mass of all elements contained in calcium iodate using the periodic table: Ca: 40.078 I: 126.90447 O: 15.999 As an intermediate step we calculate the molecular mass of the ion IO3: 126.90447 + 3*15.999 = 174.90147 Then we calculate the mass of one calcium atom and 2 iodate ions: 2*174.90147 + 40.078 = 389.88094 amu</span>
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Calculate the fraction of lattice sites that are Schottky defects for cesium chloride at 623 oC (this temperature is below the m
Degger [83]

Answer:

5.9 × 10^-6.

Explanation:

In the arrangements of crystal solids there is likely going to be an imperfection or defect and one of the defect or imperfections in the arrangements of solids is known as the Schottky defects. The Schottky defects is a kind of lattice arrangements imperfection that occurs when positively charged ions and negatively charged ions leave their position.

So, let us delve right into the solution of the question. We will be making use of the formula below;

Wb/ W = e^ - c/ 2kT.

Where Wb/ W= fraction of lattice sites, c= energy for defect formation = 1.86 eV, and T = temperature= 623° C= 896 k.

So, Wb/ W = e ^ -1.86/ (2 × 896 × 8.62 × 10^ -5).

Wb/ W= 0.000005896557435956372.

Wb/ W=5.9 × 10^-6.

3 0
3 years ago
__Na3PO4 + __Sr(NO3)2 --&gt; ___Sr3(PO4)2 + __NaNO3
lisov135 [29]

Answer:

0.0526mol

Explanation:

The chemical equation given in this equation is as follows:

Na3PO4 + Sr(NO3)2 → Sr3(PO4)2 + NaNO3

However, this equation is unbalanced as the number of atoms of each element on each side does not correlate. The balanced equation is as follows:

2Na3PO4 + 3Sr(NO3)2 → Sr3(PO4)2 + 6NaNO3

This balanced equation means that:

2 moles of Sodium Phosphate (Na3PO4) is required to react with 3 moles of Strontium Nitrate (Sr(NO3)2)

Hence, if 0.0789 moles of Strontium Nitrate are reacted, then 0.0789 × 2/3

moles of sodium phosphate will also react.

= 0.0789 × 2/3

= 0.1578/3

= 0.0526mol

5 0
3 years ago
How many moles of O2 (molar mass = 32.00 g/mol) are needed to react completely with 52.0 L of CH4 (g) at STP to produce CO2 and
Rainbow [258]
CH4 (g) + 2O2 (g) --> CO2 (g) + 2H2O (i)
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According to  the balanced reaction, you need 2 mol O2 for every 1 mol CH4. so you need 2 x 2.32 mol = 4.64 mol O2.

hope this help
6 0
3 years ago
Read 2 more answers
A reaction will NOT occur when all the reactants and products in the ionic equation are spectator ions because no change occurs
wolverine [178]
I think the correct answer from the choices listed above is option C. The substances that do not undergo chemical change when mixed are the substances  NaNO3(aq) and KI(aq). They form spectator ions. Hope this answers the question.
4 0
3 years ago
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PolarNik [594]

Answer:

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Explanation:

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