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AlekseyPX
3 years ago
12

A sample of gas in a syringe has a volume of 9.66 mL at a pressure of

Chemistry
1 answer:
Zolol [24]3 years ago
6 0
The answer is 6.58mL or 0.00658L. How I got this answer step by step is included in the photo below. Hope this helps!

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What is the molarity of an H2SO4 solution if 49.0 mL are titrated by 68.4 mL of a .333 M NaOH solution
denis23 [38]

Answer:

0.232M

Explanation:

H2SO4+2NaOH--> 2H2O+Na2SO4

(0.0684L)(.333M NaOH) = 0.0227 moles NaOH (1 mol H2SO4/2 mol NaOH)

= 0.0114 moles H2SO4

M = 0.0114 moles/ 0.0490L solution = 0.232M

* Please text me at 561-400-5105 for tutoring: I can do assignments, labs, exams, etc.  :)

8 0
3 years ago
Write the correct name for each compound. a. N2O5 b. Si2F4 c. S3F d. OF2 e. H4P6 f. C2O4 g. HF3
PSYCHO15rus [73]

Answer:

a. Boron trifluoride

b. Propane

c. Dinitrogen pentoxide

d. Carbon Dioxide

e. Silicon Octafluroride?

Explanation:

Glad to help :)

3 0
3 years ago
copper hydroxide and potassium sulfate are produced when potassium hydroxide reacts with copper sulfate balanced equation
a_sh-v [17]

This problem is requiring the balanced chemical equation that takes place when copper hydroxide and potassium sulfate are produced when reacting potassium hydroxide with copper sulfate.

<h3>Balancing chemical equations:</h3>

In chemistry, balancing chemical equations is based on the law of conservation of mass, which demands us to have equal number of atoms on both sides of the chemical equation. This can be accomplished by inserting coefficients in front of the chemical species.

For this particular case, we have potassium hydroxide with copper sulfate on the reactants side, however, copper can be copper (I) or copper (II) as it has 1+ and 2+ as its possible oxidation numbers. In addition, copper hydroxide and potassium sulfate as the products. Hence, we can assume this is all about copper (II) so we can write:

KOH+CuSO_4\rightarrow K_2SO_4+Cu(OH)_2

As we can see, potassium, hydrogen and oxygen have two atoms each on the products side, but just one on the reactants side; drawback we can overcome by putting a 2 in front of KOH so as to balance it:

2KOH+CuSO_4\rightarrow K_2SO_4+Cu(OH)_2

Learn more about balancing chemical equations: brainly.com/question/8062886

8 0
2 years ago
The reduction of nitrogen monoxide is described by the following chemical equation: 2H2 (g) +2NO (g) 2H20 ()N2 (g Suppose a two-
Ipatiy [6.2K]

Answer:

Reasonable Second step- N_{2}O(g)+H_{2}(g)\rightarrow N_{2}(g)+H_{2}O(g)

Explanation:

The given single step chemical reaction is as follows.

2H_{2}(g)+2NO \rightarrow 2H_{2}O(g)+N_{2}(g)

Suppose a two-step mechanism is proposed for this reaction,

The reaction occured in two steps they are as follows.

Step -1:H_{2}(g)+2NO \rightarrow N_{2}O(g)+H_{2}O(g)

Step-2:N_{2}O(g)+H_{2}(g)\rightarrow N_{2}(g)+H_{2}O(g)

8 0
3 years ago
Please help me which one
mel-nik [20]
Non of the above because protons and neutrons don’t mix with each one there
3 0
1 year ago
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