Answer:
The answer to the question is
The rate constant for the reaction is 1.056×10⁻³ M/s
Explanation:
To solve the question, e note that
For a zero order reaction, the rate law is given by
[A] = -k×t + [A]₀
This can be represented by the linear equation y = mx + c
Such that y = [A], m which is the gradient is = -k, and the intercept c = [A]₀
Therefore the rate constant k which is the gradient is given by
Gradient =
where [A]₁ = 8.10×10⁻² M and [A]₂ = 1.80×10⁻³ M
=
= -0.001056 M/s = -1.056×10⁻³ M/s
Threfore k = 1.056×10⁻³ M/s
Answer:
S = 7.9 × 10⁻⁵ M
S' = 2.6 × 10⁻⁷ M
Explanation:
To calculate the solubility of CuBr in pure water (S) we will use an ICE Chart. We identify 3 stages (Initial-Change-Equilibrium) and complete each row with the concentration or change in concentration. Let's consider the solution of CuBr.
CuBr(s) ⇄ Cu⁺(aq) + Br⁻(aq)
I 0 0
C +S +S
E S S
The solubility product (Ksp) is:
Ksp = 6.27 × 10⁻⁹ = [Cu⁺].[Br⁻] = S²
S = 7.9 × 10⁻⁵ M
<u>Solubility in 0.0120 M CoBr₂ (S')</u>
First, we will consider the ionization of CoBr₂, a strong electrolyte.
CoBr₂(aq) → Co²⁺(aq) + 2 Br⁻(aq)
1 mole of CoBr₂ produces 2 moles of Br⁻. Then, the concentration of Br⁻ will be 2 × 0.0120 M = 0.0240 M.
Then,
CuBr(s) ⇄ Cu⁺(aq) + Br⁻(aq)
I 0 0.0240
C +S' +S'
E S' 0.0240 + S'
Ksp = 6.27 × 10⁻⁹ = [Cu⁺].[Br⁻] = S' . (0.0240 + S')
In the term (0.0240 + S'), S' is very small so we can neglect it to simplify the calculations.
S' = 2.6 × 10⁻⁷ M
Answer:
1.23 × 10³ N
Explanation:
Step 1: Given and required data
- Mass of the person (m): 125 kg
- Acceleration due to the gravitational force (g): 9.81 m/s²
Step 2: Calculate the force acting between the Earth and a 125-kg person standing on the surface of the Earth
We will use Newton's second law of motion.
F = m × g
F = 125 kg × 9.81 m/s²
F = 1.23 × 10³ N
Answer:
1. chloroplast
2. they prevent some proteins to function how they normally function
Explanation:
Answer:
Thus, first conversion of mass of methane into moles by dividing it with 16.04 g/mol
Mass = 138.63 g
Explanation:
The balanced chemical reaction is shown below:-

Firstly the moles of methane gas reacted must be calculate as:-
Given, mass of methane = 50.6 g
Molar mass of methane gas = 16.04 g/mol
The formula for the calculation of moles is:-

Thus, from the reaction stoichiometry,
1 mole of methane produces 1 mole of carbon dioxide
Also,
3.15 mole of methane produces 3.15 mole of carbon dioxide
Moles of
= 3.15 mole
Molar mass of
= 44.01 g/mol
Mass = Moles*Molar mass =
g = 138.63 g