1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Pepsi [2]
4 years ago
6

PLEASE HELP ME PLEASE

Chemistry
1 answer:
Murljashka [212]4 years ago
6 0

Answer:

c because they are the closest together

You might be interested in
The reactant concentration in a first-order reaction was 8.10×10−2 M M after 15.0 s s and 1.80×10−3 M M after 90.0 s s . What is
kipiarov [429]

Answer:

The answer to the question is

The rate constant for the reaction is 1.056×10⁻³ M/s

Explanation:

To solve the question, e note that

For a zero order reaction, the rate law is given by

[A] = -k×t + [A]₀

This can be represented by the linear equation y = mx + c

Such that y = [A], m which is the gradient is = -k, and the intercept c = [A]₀

Therefore the rate constant k which is the gradient is given by

Gradient = \frac{[A]_{2} - [A]_{1}  }{t_{2} - t_{1}  }  where [A]₁ = 8.10×10⁻² M and [A]₂ = 1.80×10⁻³ M

= \frac{1.80*10^{-3} M- 8.10*10^{-2} M}{90 s - 15 s} = -0.001056 M/s = -1.056×10⁻³ M/s

Threfore k = 1.056×10⁻³ M/s

3 0
3 years ago
Calculate the solubility at 25°C of CuBr in pure water and in a 0.0120M CoBr2 solution. You'll find Ksp data in the ALEKS Data t
iragen [17]

Answer:

S = 7.9 × 10⁻⁵ M

S' = 2.6 × 10⁻⁷ M

Explanation:

To calculate the solubility of CuBr in pure water (S) we will use an ICE Chart. We identify 3 stages (Initial-Change-Equilibrium) and complete each row with the concentration or change in concentration. Let's consider the solution of CuBr.

    CuBr(s) ⇄ Cu⁺(aq) + Br⁻(aq)

I                       0             0

C                     +S           +S

E                       S             S

The solubility product (Ksp) is:

Ksp = 6.27 × 10⁻⁹ = [Cu⁺].[Br⁻] = S²

S = 7.9 × 10⁻⁵ M

<u>Solubility in 0.0120 M CoBr₂ (S')</u>

First, we will consider the ionization of CoBr₂, a strong electrolyte.

CoBr₂(aq) → Co²⁺(aq) + 2 Br⁻(aq)

1 mole of CoBr₂ produces 2 moles of Br⁻. Then, the concentration of Br⁻ will be 2 × 0.0120 M = 0.0240 M.

Then,

    CuBr(s) ⇄ Cu⁺(aq) + Br⁻(aq)

I                       0           0.0240

C                     +S'           +S'

E                       S'            0.0240 + S'

Ksp = 6.27 × 10⁻⁹ = [Cu⁺].[Br⁻] = S' . (0.0240 + S')

In the term (0.0240 + S'), S' is very small so we can neglect it to simplify the calculations.

S' = 2.6 × 10⁻⁷ M

8 0
3 years ago
HELP IM AB TO CRY
Lemur [1.5K]

Answer:

1.23 × 10³ N

Explanation:

Step 1: Given and required data

  • Mass of the person (m): 125 kg
  • Acceleration due to the gravitational force (g): 9.81 m/s²

Step 2: Calculate the force acting between the Earth and a 125-kg person standing on the surface of the Earth

We will use Newton's second law of motion.

F = m × g

F = 125 kg × 9.81 m/s²

F = 1.23 × 10³ N

8 0
3 years ago
Answer the following questions. When you have finished, submit this assignment to your teacher by the due date for full credit.
Stells [14]

Answer:

1. chloroplast

2. they prevent some proteins to function how they normally function

Explanation:

3 0
2 years ago
Which conversion factor do you use first to calculate the number of grams of CO 2 produced by the reaction of 50.6 g of CH 4 wit
Brilliant_brown [7]

Answer:

Thus, first conversion of mass of methane into moles by dividing it with 16.04 g/mol

Mass =  138.63 g

Explanation:

The balanced chemical reaction is shown below:-

CH_4+2O_2\rightarrow CO_2+2H_2O

Firstly the moles of methane gas reacted must be calculate as:-

Given, mass of methane = 50.6 g

Molar mass of methane gas = 16.04 g/mol

The formula for the calculation of moles is:-

Moles=\frac{Mass\ taken}{Molar\ mass}=\frac{50.6}{16.04}\ mol=3.15\ mol

Thus, from the reaction stoichiometry,

1 mole of methane produces 1 mole of carbon dioxide

Also,

3.15 mole of methane produces 3.15 mole of carbon dioxide

Moles of CO_2 = 3.15 mole

Molar mass of CO_2 = 44.01 g/mol

Mass = Moles*Molar mass = 3.15\times 44.01 g = 138.63 g

3 0
3 years ago
Other questions:
  • What is the major product of the calvin-benson cycle that can then be used to form glucose?
    15·1 answer
  • A 67.2 g sample of a gold and palladium alloy contains 3.28×1023 atoms .
    12·1 answer
  • do you guys just sit and answer questions for fun or is it your job because that just sounds lame as shiit. I would like to know
    11·2 answers
  • What causes windy conditions at the coast in the summer?
    7·1 answer
  • The equilibrium constant for the chemical equation is Kp = 5.23 at 191 °C. Calculate the value of the Kc for the reaction at 191
    6·1 answer
  • How much heat is needed to boil 45 grams of water at 100°C?​
    8·1 answer
  • A white substance melts with some decomposition at 730oC. As a solid it does not conduct electricity, but it dissolves in water
    14·1 answer
  • A certain first-order reaction (A→products) has a rate constant of 8.10×10−3 s−1 at 45 ∘C. How many minutes does it take for the
    12·1 answer
  • can someone make me a lab report? Please......... Objective(s): In your own words, what was the purpose of this lab? Hypothesis:
    14·2 answers
  • Data that is collected that is mostly numbers?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!