Answer:
Posible dimers structures: B) and D) (Figure 1)
Explanation:
The correct <u>dimer structures</u> are the ones that have a right <u>intermolecular bonding</u> interacction. In this case we will have hydrogen bonding. This type of interaction is due to the negative polarization in the oxygen and the positive polarization in the hydrogen. (Figure 2)
So, a correct dimer structure is posible if we have an interaction from the negative part (oxygen) to the positive part (hydrogen). The only structures that have this type of interactions are B and D.
Explanation:
As technology advances with time, it also enhances people's creativity. ... People are able to constantly search things and discover new information they didn't know before. It allows us to become educated and have an outlet to speak our mind
Hi , these are the definitions
Chemistry; the science that deals with the composition and properties of substances and various elementary forms of matter.
aquatic system ; ecosystem in a body of water , communities and organisms that are dependent on each other.
depth ; the distance from the top to the bottom of something .
geography ; the study of the earth s physical features and the people ,plants , and animals.
light ; brightness from the sun or from a light.
medium ; between small and large in size.
period ; the name given to a horizontal row of the periodic table.
properties ; attributes of a substance.
refraction ; the change of direction of a ray of light , sound , heat ....
reflection ; reflection is when infrared waves bounce from a surface .
salinity ; a saline substance or a liquid that contains salt.
pressure ; measure of the force applied over an unit area .
photosynthesis ; the process used by plants , algae , and certain bacteria to harness energy from sunlight into chemical energy.
thermocline ; an abrupt temperature gradient in a body of water .
intertidal ; relating to the region between the hide tide mark and the low tide mark .
benthic ; relating to the bottom of a sea or a lake or to the organisms that live there .
pelagic ; relating to or living in the sea far from the shore.
epipelagic ; relating to or inhabiting the uppermost layer of the water column of the open ocean , into which enough sunlight enters for photosynthesis to take place.
mesopelagic ; relating to or inhabiting the layer of the water column in the open sea that lies between the epipelagic and bathypelagic layers at depths of about 200 to 1,000 meters.
bathypelagic ; relating to or inhabiting the layer of the water column of the open sea that lies between the mesopelagic and abyssopelagic layers at depths of about 1,000 to 4,000.
abyssopelagic ; refering to or occurring in the region of deep water above the floor of the ocean .
neritic ; region of water lying directly above the sub littoral zone of the sea bottom .
photic ; pertaining to the generation of light by organisms .
aphotic; zone of an ocean , lowest level at which photosynthesis can take place .
commensalism ; type of a relationship between a plant , an animal , fungus , etc.
competition ; the struggle among organisms .
freshwater systems ; subset of earth s aquatic ecosystems .
marine systems ; inside aquatic system , marine systems include oceans , seas ,etc.
mutual ism ; relation between species of organisms in which both benefit from the association.
organism ; a system with many parts that depends on each other and work together.
parasitism ; the behavior of a parasite .
predation; preying or plundering.
relationships ; the way in which two things are connected .
terrestrial systems ; an ecosystem only found on land forms.
<span />
Answer:
Covalent bonds are formed when electrons are shared between elements that are nonmetals. The ammonium ion, NH+4 , would have covalent bonds because both nitrogen and hydrogen are nonmetals. ... The rest of the bonds all contain electrons from both hydrogen and nitrogen, so they would be considered ordinary covalent bonds.
Answer:
Without doing any calculations it is possible to determine that silver chromate is more soluble than <u>C,D ,</u> and silver chromate is less soluble than <u>none</u> .
It is not possible to determine whether silver chromate is more or less soluble than <u>A,B</u> by simply comparing Kspvalues
Explanation:
For this kind of question you need to obtain the balanced equation for the solubility, first, you will write the dissociation equation for every molecule, obtaining the ions in which it dissociates. Then you substitute in the Kps equation
![A_{n}B_{m} -> nA^{m+}+mB^{n-} \\K_{s}=[A^{m}]^{n}[B^{n}]^{m}](https://tex.z-dn.net/?f=A_%7Bn%7DB_%7Bm%7D%20-%3E%20nA%5E%7Bm%2B%7D%2BmB%5E%7Bn-%7D%20%5C%5CK_%7Bs%7D%3D%5BA%5E%7Bm%7D%5D%5E%7Bn%7D%5BB%5E%7Bn%7D%5D%5E%7Bm%7D)
Considering the corresponding stoichiometry you'll substitute in your dissociation equations as follow.
![Ag_{2}CrO_{4}(s)->2Ag^{+}(aq)+CrO_{4} ^{2-}\\ s ->2s+s\\s->[2s]^{2}[s]=4s^{3} \\\\A) PbF_{2}(s)->Pb^{2+} (aq)+2F^{-}\\s->s+2s\\s->[s][2s]^{2}=4s^{3}\\\\\\B)Ag_{2}SO_{3}(s)->2Ag^{+}(aq)+SO_{3} ^{2-}\\ s ->2s+s\\s->[2s]^{2}[s]=4s^{3} \\\\\\C)NiCO_{3}(s)->Ni^{2+}(aq)+CO_{3} ^{2-}\\ s ->s+s\\s->[s][s]=s^{2} \\\\\\D)AgCl(s)->Ag^{+}(aq)+Cl^{-}(aq)\\ s ->s+s\\s->[s][s]=s^{2} \\](https://tex.z-dn.net/?f=Ag_%7B2%7DCrO_%7B4%7D%28s%29-%3E2Ag%5E%7B%2B%7D%28aq%29%2BCrO_%7B4%7D%20%5E%7B2-%7D%5C%5C%20%20%20%20%20%20%20%20s%20%20-%3E2s%2Bs%5C%5Cs-%3E%5B2s%5D%5E%7B2%7D%5Bs%5D%3D4s%5E%7B3%7D%20%20%5C%5C%5C%5CA%29%20%20PbF_%7B2%7D%28s%29-%3EPb%5E%7B2%2B%7D%20%28aq%29%2B2F%5E%7B-%7D%5C%5Cs-%3Es%2B2s%5C%5Cs-%3E%5Bs%5D%5B2s%5D%5E%7B2%7D%3D4s%5E%7B3%7D%5C%5C%5C%5C%5C%5CB%29Ag_%7B2%7DSO_%7B3%7D%28s%29-%3E2Ag%5E%7B%2B%7D%28aq%29%2BSO_%7B3%7D%20%5E%7B2-%7D%5C%5C%20%20%20%20%20%20%20%20s%20%20-%3E2s%2Bs%5C%5Cs-%3E%5B2s%5D%5E%7B2%7D%5Bs%5D%3D4s%5E%7B3%7D%20%20%5C%5C%5C%5C%5C%5CC%29NiCO_%7B3%7D%28s%29-%3ENi%5E%7B2%2B%7D%28aq%29%2BCO_%7B3%7D%20%5E%7B2-%7D%5C%5C%20%20%20%20%20%20%20%20s%20%20-%3Es%2Bs%5C%5Cs-%3E%5Bs%5D%5Bs%5D%3Ds%5E%7B2%7D%20%20%5C%5C%5C%5C%5C%5CD%29AgCl%28s%29-%3EAg%5E%7B%2B%7D%28aq%29%2BCl%5E%7B-%7D%28aq%29%5C%5C%20%20%20%20%20%20%20%20s%20%20-%3Es%2Bs%5C%5Cs-%3E%5Bs%5D%5Bs%5D%3Ds%5E%7B2%7D%20%20%5C%5C)
IIn this case, the silver chromate has a Kps of
, same as the compound in options A and B, comparing these numbers you can't determine which one is bigger. Finally, options C and D have a kps of
, this value is smaller than silver chromate's kps.
I hope you find this information useful! good luck!