Answer:
P=mv 2250*25=56250
Explanation:
p of truck =2250*25 =56250
since p of truck = p of car
then p of car = 56250
therefore p of car = 1210 * v
or, 56520=1210v
or,v= 56520/1210=46.48
so, v of car is 46.48m/s
Since the connection is in series, the current divider can be used. It's mathematical expression is In = (It Rt) / Rn. If the value for is solved, power dissipation can also be solved using P = I^2 R.
I = 0.47 A
A. P = (0.47)^2 (5) = 1.11 Watts
B. P = (0.47)^2 (9) = 2 Watts
C. P = VI = 16(0.47) 4.24 Watts
Answer:
-0.4 m/s
-3.552 m/s
Explanation:
= Mass of first glider = 0.5 kg
= Mass of second glider = 0.3 kg
= Initial Velocity of first glider = 2 m/s
= Initial Velocity of second glider = -2 m/s
= Final Velocity of first glider
= Final Velocity of second glider = 2 m/s
As the linear momentum of the system is conserved we have

The velocity of glider A is -0.4 m/s
= 0
= -5 m/s
= 0.92 m/s

The velocity of glider A is -3.552 m/s
It goes into a supernova I think
Explanation:
This problem seeks to ensure that the student comprehends the meaning of precision and accuracy.
These two key terms are used to express how reliable experimental values obtained are.
- Precision is the ability to consistently reproduce a result.
- Accuracy is the nearness of the measure value to the true value.
- The different between the measured and true values gives the error in the result.
In the problem given, the most accurate reading would be one that has value close to the standard mass of 150g. Any student that reports this value would be reported as accurate.
The precise reading would be for the student that is able to repeatedly produce the same kind of values. This is irrespective of whether the values are close to the true value or not.
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