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GarryVolchara [31]
3 years ago
9

A 20-kg block slides down a fixed rough curved track The block has a speed of 5 0 m/s after its height above a horizontal surfac

e has
decreased by 1.8 m. Assume the block starts from rest. How much work is done on the block by the force of friction during this descent?​
Physics
1 answer:
Crank3 years ago
8 0

Answer:

U = 102.8 J (100 J to two significant digits)

Explanation:

potential energy converted = 20(9.8)(1.8) = 352.8 J

kinetic energy at base of track = ½(20)5.0² = 250 J

energy (work) of friction 352.8 - 250 = 102.8 J

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What velocity must a 1210 kg car have in order to have the same momentum as the pickup truck in the sample problem
harina [27]

Answer:

P=mv 2250*25=56250

Explanation:

p of truck =2250*25 =56250

since p of truck = p of car

then p of car = 56250

therefore p of car = 1210 * v

or, 56520=1210v

or,v= 56520/1210=46.48

so, v of car is 46.48m/s

3 0
3 years ago
Part A
kakasveta [241]
Since the connection is in series, the current divider can be used. It's mathematical expression is In = (It Rt) / Rn. If the value for is solved, power dissipation can also be solved using P = I^2 R. 
I = 0.47 A 
A.  P = (0.47)^2 (5) = 1.11 Watts
B. P = (0.47)^2 (9) = 2 Watts
C. P = VI = 16(0.47) 4.24 Watts 
4 0
4 years ago
Read 2 more answers
Two gliders move toward each other on a linear air track, which we assume is frictionless. Glider A has a mass of 0.50 kg, and g
Nataly_w [17]

Answer:

-0.4 m/s

-3.552 m/s

Explanation:

m_1 = Mass of first glider = 0.5 kg

m_2 = Mass of second glider = 0.3 kg

u_1 = Initial Velocity of first glider = 2 m/s

u_2 = Initial Velocity of second glider = -2 m/s

v_1 = Final Velocity of first glider

v_2 = Final Velocity of second glider = 2 m/s

As the linear momentum of the system is conserved we have

m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\Rightarrow v_1=\dfrac{m_1u_1+m_2u_2-m_2v_2}{m_1}\\\Rightarrow v_1=\dfrac{0.5\times 2+0.3\times (-2)-0.3\times 2}{0.5}\\\Rightarrow v_1=-0.4\ m/s

The velocity of glider A is -0.4 m/s

u_1 = 0

u_2 = -5 m/s

v_2 = 0.92 m/s

m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\Rightarrow v_1=\dfrac{m_1u_1+m_2u_2-m_2v_2}{m_1}\\\Rightarrow v_1=\dfrac{0.5\times 0+0.3\times (-5)-0.3\times 0.92}{0.5}\\\Rightarrow v_1=-3.552\ m/s

The velocity of glider A is -3.552 m/s

8 0
3 years ago
Once a supergiant fuses all of its hydrogen into helium, what happens in the core?
DanielleElmas [232]
It goes into a supernova I think
3 0
3 years ago
Four students measure the mass of a standard mass that has an accepted value of 150.0 g. They post their results in a table.
Eddi Din [679]

Explanation:

This problem seeks to ensure that the student comprehends the meaning of precision and accuracy.

These two key terms are used to express how reliable experimental values obtained are.

  • Precision is the ability to consistently reproduce a result.
  • Accuracy is the nearness of the measure value to the true value.
  • The different between the measured and true values gives the error in the result.

In the problem given, the most accurate reading would be one that has value close to the standard mass of 150g. Any student that reports this value would be reported as accurate.

The precise reading would be for the student that is able to repeatedly produce the same kind of values. This is irrespective of whether the values are close to the true value or not.

learn more:

Statistics brainly.com/question/4401748

#learnwithBrainly

4 0
3 years ago
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