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GarryVolchara [31]
3 years ago
9

A 20-kg block slides down a fixed rough curved track The block has a speed of 5 0 m/s after its height above a horizontal surfac

e has
decreased by 1.8 m. Assume the block starts from rest. How much work is done on the block by the force of friction during this descent?​
Physics
1 answer:
Crank3 years ago
8 0

Answer:

U = 102.8 J (100 J to two significant digits)

Explanation:

potential energy converted = 20(9.8)(1.8) = 352.8 J

kinetic energy at base of track = ½(20)5.0² = 250 J

energy (work) of friction 352.8 - 250 = 102.8 J

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2 years ago
You fire a projectile 35° above horizontal with an initial velocity of 200m/s. It lands in a valley 300m below the launch point.
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Answer:

See below

Explanation:

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<u />

To find the range

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Horizontal component of initial velocity    200 cos 35 = 163.83 m/s

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2 years ago
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3 years ago
Read 2 more answers
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