Answer:
Increase
As the mass of either object increases, the force of gravitational attraction between them also increases.
Explanation:
The gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force.
As the mass of either object increases, the force of gravitational attraction between them also increases.
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Answer:
B
Explanation:
The question does not specify any outside forces that could slow down the ball horizontally. There fore the ball does not accelerate or decelerate horizontally. Therefore, a = 0m/s2
Answer:
check the attachments for the solution
Answer:
See below
Explanation:
Vertical component of initial velocity = 200 sin 35° = 114.72 m/s
then use position formula a = 9.81 m/s^2
0 = 300 + 114.72 t - 1/2 (9.81)(t^2)
use quadratic formula with a = - 4.905 b = 114.72 c = 300
to find t = <u>25.76 seconds </u>
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To find the range
( horizontal distance the projectile lands from launch point)
Horizontal component of initial velocity 200 cos 35 = 163.83 m/s
( it flies horizontally at this speed for <u>25.76 seconds <==found above</u>)
163.83 m/s * 25.76 s = <u>4220.3 meters</u>
One should never anchor in a narrow channel, until unless required very importantly. One should stay to the starboard side, and use a prolonged blast. The announcement must be done to alarm the nearby vessels, about your approach. The vessel should be kept at the outer limit of the starboard side.
