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GarryVolchara [31]
3 years ago
9

A 20-kg block slides down a fixed rough curved track The block has a speed of 5 0 m/s after its height above a horizontal surfac

e has
decreased by 1.8 m. Assume the block starts from rest. How much work is done on the block by the force of friction during this descent?​
Physics
1 answer:
Crank3 years ago
8 0

Answer:

U = 102.8 J (100 J to two significant digits)

Explanation:

potential energy converted = 20(9.8)(1.8) = 352.8 J

kinetic energy at base of track = ½(20)5.0² = 250 J

energy (work) of friction 352.8 - 250 = 102.8 J

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A mass m neutron has elastic collision with a mass m'
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Read 2 more answers
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hence the error is -\frac{0.381}{9.801} *100

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the error is not so high,so it can be  accepted.

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As the experiment is done under air resistance,so it will affect to the time period.hence the time period will be more which in turn decreases the value of g.

if this experiment is done in a environment of zero air resistance,we will get the value of g which must be approximately equal to 9.801  m/s^2

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