Need help with this trigonometry word problem
2 answers:
The distance between the tree and the tower is 30√3m.
Justification:
<u>Let the situation be in a right angleABC form as shown in attached figure</u>.
<u>Given the height of the tower is 30m and the angle of depression to the base of the tree measure 30°</u>.
So, In ΔABC
tanθ = p/b
tan30° = 30/BC
1/√3 = 30/BC
BC = 30√3m.
Answer:
30√3 m ≈ 52 m
Step-by-step explanation:
The side ratios in a 30°-60°-90° triangle are 1 : √3 : 2. The long leg of the triangle is √3 times 30 m, or about 51.96 m.
The distance between the tree and the tower is about 30√3 m ≈ 52 m.
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If you haven't memorized the ratios of this special triangle, you can use the relation ...
Tan = Opposite/Adjacent
tan(30°) = 30/d
d = 30/tan(30°) = 30√3 = 51.96 . . . . same as above
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Answer:
There is a 50% probability that the household has a dog, given that the household has a cat.
Step-by-step explanation:
We solve this problem building the Venn's diagram of these probabilities.
I am going to say that:
A is the probability that a household has a cat.
B is the probability that a household has a dog.
We have that:
In which a is the probability that a household has a cat but not a dog and is the probability that a household has both a cat and a dog.
By the same logic, we have that:
The probability that the household has a cat or a dog is 0.5
The probability that the household has a dog is 0.4
The probability that the household has a cat is 0.2.
So
What is the probability that the household has a dog, given that the household has a cat?
20% of the households have a cat, and 10% have both a cat and a dog. So
There is a 50% probability that the household has a dog, given that the household has a cat.