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Ksju [112]
3 years ago
10

Need help with this trigonometry word problem

Mathematics
2 answers:
creativ13 [48]3 years ago
6 0

The distance between the tree and the tower is 30√3m.

Justification:

<u>Let the situation be in a right angleABC form as shown in attached figure</u>.

<u>Given the height of the tower is 30m and the angle of depression to the base of the tree measure 30°</u>.

So, In ΔABC

tanθ = p/b

tan30° = 30/BC

1/√3 = 30/BC

BC = 30√3m.

Alja [10]3 years ago
3 0

Answer:

  30√3 m ≈ 52 m

Step-by-step explanation:

The side ratios in a 30°-60°-90° triangle are 1 : √3 : 2. The long leg of the triangle is √3 times 30 m, or about 51.96 m.

The distance between the tree and the tower is about 30√3 m ≈ 52 m.

__

If you haven't memorized the ratios of this special triangle, you can use the relation ...

  Tan = Opposite/Adjacent

  tan(30°) = 30/d

  d = 30/tan(30°) = 30√3 = 51.96 . . . . same as above

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Step-by-step explanation:

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Simplify the problem
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Amelia's water bottle holds 4 pints, 2 cups. How many cups does Amelia's water bottle hold? Note: 1 pint = 2 cups​
ivann1987 [24]

Answer:

10 cups

Step-by-step explanation:

4x2=8. 8+ the 2 cups in the beginning would be 10 cups.

3 0
3 years ago
I need help with #61 to #64 ASAP please and thank you …. Could someone please help me with it… I need to get it done ASAP
aivan3 [116]

Problem 61

The nth triangular number is

T(n) = n(n+1)/2

I'll rewrite this into

T(n) = 0.5n(n+1)

The triangular number right after this is

T(n+1) = 0.5(n+1)(n+2)

I replaced every n with n+1 and simplified

Let's see what we get when we add up the two expressions

T(n) + T(n+1)

0.5n(n+1) + 0.5(n+1)(n+2)

0.5n^2+0.5n + 0.5(n^2+3n+2)

0.5n^2 + 0.5n + 0.5n^2 + 1.5n + 1

n^2+2n+1

(n+1)^2

This shows that the sum of any two consecutive triangular numbers results in a square number

Here's a few examples

  • 0+1 = 1
  • 1+3 = 4
  • 3+6 = 9
  • 6+10 = 16
  • 10+15 = 25

Note each sum is a perfect square, which visually would plot out a square figure.

For quick reference, the set of the first few triangular numbers is {0, 1, 3, 6, 10, 15, 21, 28, 36, 45, 55,...}

<h3>Answer: Square number</h3>

==========================================================

Problem 64

Let's say we go with n = 5.

This means,

T(n) = 0.5n(n+1)

T(n-1) = 0.5(n-1)(n-1+1)

T(n-1) = 0.5n(n-1)

T(5-1) = 0.5*5(5-1)

T(4) = 10

This says that when n = 5, the 4th triangular number is 10

Triple that result and add on n = 5

3*T(4) + n = 3*10+5 = 35

This result is beyond obvious which category of figurate number it belongs to. It's not a triangular number since it's not in the form n(n+1)/2. It's not a square number either.

Through a bit of trial and error, you should find it's a pentagonal number

Pentagonal numbers are of the form n(3n-1)/2

If you plugged n = 5 into that, it leads to 35

n(3n-1)/2 = 5*(3*5-1)/2 = 5*14/2 = 70/2 = 35

The diagram shown below represents the first few pentagonal numbers. The number of blue dots corresponds to the pentagonal number itself. Note the equal spacing when dealing with dots on each segment (eg: some interior blue dots are midpoints, others are quarter points, etc.)

<h3>Answer: Pentagonal number</h3>

8 0
2 years ago
Pls awnser these i dont understand them, like i beg u
Gekata [30.6K]
It’s not a good idea to beg
4 0
3 years ago
Read 2 more answers
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