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Anastasy [175]
2 years ago
12

Match the separation techniques with the correct descriptions.

Chemistry
1 answer:
nordsb [41]2 years ago
4 0

Answer:

Explanation:

1 = A

Sublimation is the process where by a sample is heated to pass through solid phase to gaseous phase without the intermittent liquid phase. Example of substance that sublime is camphor.

2 = D

Decantantion

5 = F

Filtration is the process a liquid from solid using a porous material. This technique requires a set up and a good porous material eg filter paper.

6 = B

This technique is to separate a mixture of solids by converting them from solid phase to gaseous phase since they sublime.

3 = deposition.

The answer isn't in the option but deposition is the process of substance in gaseous phase to change into solid state without passing through liquid phase. Deposition is the opposite of sublimation.

4 = E

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explain why benzoic acid is insolube in water at room temperature but is soluble in 2.5M NaOH solution
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Answer:

It is known generally that polar compounds are soluble in polar solvents. Based on the structure of benzoic acid, it comprises the non-polar C6H6 group and polar COOH group. Based on the structure, in benzoic acid, the nonpolar hydrocarbon outweighs and influences the polar part as nonpolar, due to which benzoic acid is not soluble in water.

On the other hand, benzoic acid produces sodium salt benzoic acid when it reacts with 2.5 M sodium hydroxide, this salt is ionic. Generally, the ionic compounds are soluble in water. Therefore, the salt of benzoic acid gets dissolved in water. Hence, benzoic acid is soluble in the solution of sodium hydroxide.

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Describe all lab equipment which would be required if you wanted to heat a chemical to 1500ºC.
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Read 2 more answers
A 0.853-g of 90.0% lithium chlorate mixture decomposes with heat to give 313 ml of oxygen gas collected over water at 20 c and 7
SpyIntel [72]

Answer:

\%LiClO_3=90.4\%

Explanation:

Hello!

In this case, since the undergoing chemical reaction is:

LiClO_4\rightarrow LiCl+\frac{3}{2} O_2

It is widely known that when a gas given off from a reaction is collected over water, we can compute its pressure by minusing the total pressure 762 mmHg and the vapor pressure of water at the experiment's temperature (20 °C) in this case 17.5 mmHg as shown below:

p_{O_2}=762mmHg-17.5mmHg=744.5mmHg*\frac{1atm}{760mmHg}=0.980atm

Next, by using the ideal gas equation we compute the yielded moles of oxygen considering the collected 313 mL (0.313 L):

n_{O_2}=\frac{PV}{RT}=\frac{0.980atm*0.313L}{0.082\frac{atm*L}{mol*K}*293.15K}\\\\  n_{O_2}=0.0128molO_2

Now, via the 3/2:1 mole ratio between oxygen and lithium chlorate (molar mass = 90.39 g/mol), we compute the original mass of decomposed lithium chlorate as follows:

m_{LiClO_3}=0.0128molO_2*\frac{1molLiClO_3}{3/2molO_2}*\frac{90.39gLiClO_3}{1molLiClO_3}  \\\\m_{LiClO_3}=0.771gLiClO_3

Now, the percentage is computed as shown below:

\%LiClO_3=\frac{0.771g}{0.853g} *100\%\\\\\%LiClO_3=90.4\%

Best regards!

3 0
2 years ago
Help!!! For chemistry ​
ANEK [815]

Answer:

2KMnO₄ + 4SO₂ + H₂ ⟶ K₂SO₄ + 2MnSO₄ + H₂SO₄

Explanation:

KMnO₄ + SO₂ + H₂ ⟶ K₂SO₄ + MnSO₄ + H₂SO₄

<u>Balanced Equation</u>

2KMnO₄ + 4SO₂ + H₂ ⟶ K₂SO₄ + 2MnSO₄ + H₂SO₄

<u>-TheUnknownScientist</u>

7 0
2 years ago
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