Answer:
(A) Adding Nitrogen
Explanation:
R11 or R123 are flammable substance under certain conditions when mixed with Oxygen, adding Nitrogen is a safety procedure used in displacing any R11 or R123 which are considered as hazardous when mixed with Oxygen.
Answer:
See step by step explanations for answer.
Explanation:
600 megawatts =
568 690.272 btu / second
thermal eficiency=work done/Heat supllied
0.38=568690.272/Heat supplied
Heat supplied=1496553.35btu /s
heat emmitted to the atmosphere=heat supplied -work done=(1496553.35-568690.272)=927863.1 btu/s
feed rate=(1496553.35)/12000=124.71 lb/s =10775184.1056 lb/day=5 387.472 ton / day
sulphur content released=(0.03*124.71)/(1.496553)=2.5 lb SO2/million Btu of heat input
so
the degree (%) of sulfur dioxide control needed to meet an emission standard=(2.5/0.15)*100=1666.67 %
the CO2 emission rate=220*(1.496553) =329.241 lb/s =12 903.0802 metric ton / day
Answer:
127.42m
Explanation:
The air pressure can be understood as the weight exerted by the air column on a body, for this case we must remember that the pressure is calculated by the formula P=αgh, Where P=pressure, h=gravity, h= height,α=density
So what we must do to solve this problem is to find the length of the air column above and below the building and then subtract them to find the height of the building, taking into account the above the following equation is inferred
h2-h1= building height=H

P1=100kPa=100.000Pa
P2=98.5kPa=98.500Pa
α=1.2 kg/m^3
g=9.81m/s^2

Answer:
a) Pelton Turbine
b) 
Explanation:
From the question we are told that:
Height 
Flow Rate 
Rotational speed 
Let
Density of water

Generally the equation for momentum is mathematically given by



Answer:
Explanation:
Low frequency gain is= 40db= 20logK=>100 poles at 2MHz,20MHz
Zero at -200MHz, zero at infinity.
A) A(s) = 100FH(s)
B) Poles (1): 2 pi × 2 × 10^6= 4pi × 10^6MHz
(2): 2pi × 20 × 10^6= 4pi × 10^6 MHz
Zeroed: 2pi × 10^6 × 200= 400pi × 10^6, at infinity.
T/(S) = (1 + S/400π × 10^6)/S(1 + S/4π × 10^6)(1 + S/4π × 10^6)