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kobusy [5.1K]
3 years ago
15

Calculate the unit length of a roof using common rafters if the unit run is 7 inches. Round your answer to two decimal places.

Engineering
1 answer:
elena-14-01-66 [18.8K]3 years ago
4 0

Answer:

Explanation:

https://www.pole-barn.info/roof-rafter-calculations.html

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Under EPA's regulations, which of the following methods can be used to pressurize an R11 or R123 system for the purpose of openi
Natasha2012 [34]

Answer:

(A) Adding Nitrogen

Explanation:

R11 or R123 are flammable substance under certain conditions when mixed with Oxygen, adding Nitrogen is a safety procedure used in displacing any R11 or R123 which are considered as hazardous when mixed with Oxygen.

7 0
3 years ago
A 600 MW coal-fired power plant has an overall thermal efficiency of 38%. It is burning coal that has a heating value of 12,000
velikii [3]

Answer:

See step by step explanations for answer.

Explanation:

600 megawatts =

568 690.272 btu / second

thermal eficiency=work done/Heat supllied

0.38=568690.272/Heat supplied

Heat supplied=1496553.35btu /s

heat emmitted to the atmosphere=heat supplied -work done=(1496553.35-568690.272)=927863.1 btu/s

feed rate=(1496553.35)/12000=124.71 lb/s =10775184.1056 lb/day=5 387.472 ton / day

sulphur content released=(0.03*124.71)/(1.496553)=2.5 lb SO2/million Btu of heat input

so

the degree (%) of sulfur dioxide control needed to meet an emission standard=(2.5/0.15)*100=1666.67 %

the CO2 emission rate=220*(1.496553) =329.241 lb/s =12 903.0802 metric ton / day

5 0
3 years ago
The atmospheric pressure at the top and the bottom of a building is read by a barometer to be 98.5 kPa and 100 kPa, respectively
Fynjy0 [20]

Answer:

127.42m

Explanation:

The air pressure can be understood as the weight exerted by the air column on a body, for this case we must remember that the pressure is calculated by the formula  P=αgh, Where P=pressure, h=gravity, h= height,α=density

So what we must do to solve this problem is to find the length of the air column above and below the building and then subtract them to find the height of the building, taking into account the above the following equation is inferred

h2-h1= building height=H

H=\frac{P1-P2}{g\alpha }

P1=100kPa=100.000Pa

P2=98.5kPa=98.500Pa

α=1.2 kg/m^3

g=9.81m/s^2

H=\frac{100000-98500}{(9.81)(1.2) }=127.42m

4 0
4 years ago
1. A hydro facility operates with an elevation difference of 50 m and a flow rate of 500 m3/s. If the rotational speed is 90 RPM
zloy xaker [14]

Answer:

a) Pelton Turbine

b) P=2.42*10^{5}KW

Explanation:

From the question we are told that:

Height h=50

Flow Rate R= 500 m^3/s

Rotational speed \omega=\90 RPM

Let

Density of water

\rho=1000

Generally the equation for momentum is mathematically given by

P=\rho gRh

P=1000*9.81*500*50

P=2.42*10^{5}KW

8 0
3 years ago
A direct-coupled amplifier has a low-frequency gain of 40 dB, poles at 2 MHz and 20 MHz, a zero on the negative real axis at 200
rewona [7]

Answer:

Explanation:

Low frequency gain is= 40db= 20logK=>100 poles at 2MHz,20MHz

Zero at -200MHz, zero at infinity.

A) A(s) = 100FH(s)

B) Poles (1): 2 pi × 2 × 10^6= 4pi × 10^6MHz

              (2): 2pi × 20 × 10^6= 4pi × 10^6 MHz

 Zeroed: 2pi × 10^6 × 200= 400pi × 10^6, at infinity.

T/(S) = (1 + S/400π × 10^6)/S(1 + S/4π × 10^6)(1 + S/4π × 10^6)

8 0
3 years ago
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