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3 years ago

Thanks for the help!

Engineering

1 answer:

Dafna11 [192]3 years ago

6 0

Answer:

the 1st one i think

Explanation:

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Technician A says independent shops are not affiliated with vehicle manufacturers, but it is easy for technicians who work in th

KatRina [158]

Answer:

Explanation:

i did it yeater dayajsbs

8 0

2 years ago

An object whose mass is 251 kg is located at an elevation of 24 m above the surface of the earth. For g-9.78 ms, determine the g

Harlamova29_29 [7]

Answer:

Gravitational Potential =58.914 KJ

Explanation:

We know that

$Gravitational Potential Energy = mass\times g\times Height$

Given mass = 251 kg

Height= 24 m

g is acceleration due to gravity = $9.78m/s^{2}$

Applying values in the equation we get

$Gravitational Potential Energy=251X9.78X24 Joules$

$Gravitational Potential Energy=58914.72 Joules$

$Gravitational Potential Energy =\frac{58914.72}{1000}KJ= 58.914KJ$

4 0

3 years ago

a sprue is 12 in long and has a diameter of 5 in at the top. The molten metal level in the pouring basing is taken to be 3 in fr

vampirchik [111]

Answer:

See explaination

Explanation:

We can describe Aspiration Effect as a phenomenon of providing an allowance for the release of air from the mold cavity during the metal pouring.

See the attached file for detailed solution of the given problem.

8 0

2 years ago

Read 2 more answers

A gas turbine receives a mixture having the following molar analysis: 10% CO2, 19% H2O, 71% N2 at 720 K, 0.35 MPa and a volumetr

Sliva [168]

Answer:

2074.2 KW

Explanation:

Determine power developed at steady state

First step : Determine mass flow rate ( m )

m / Mmax = ( AV )₁ P₁ / RT₁ -------------------- ( 1 )

 where : ( AV )₁ = 8.2 kg/s, P₁ = 0.35 * 10^6 N/m^2, R = 8.314 N.M / kmol , 

 T₁ = 720 K . 

insert values into equation 1

m = 0.1871 kmol/s ( mix )

Next : calculate power developed at steady state ( using ideal gas tables to get the h values of the gases )

W( power developed at steady state )

W = m [ Yco2 ( h1 - h2 )co2

Attached below is the remaining part of the detailed solution

4 0

3 years ago

In order to fill a tank of 1000 liter volume to a pressure of 10 atm at 298K, an 11.5Kg of the gas is required. How many moles o

lesya [120]

Answer:

The molecular weight will be "28.12 g/mol".

Explanation:

The given values are:

Pressure,

P = 10 atm

= $10\times 101325 \ Pa$

= $1013250 \ Pa$

Temperature,

T = 298 K

Mass,

m = 11.5 Kg

Volume,

V = 1000 r

= $1 \ m^3$

R = 8.3145 J/mol K

Now,

By using the ideal gas law, we get

⇒ $PV=nRT$

⇒ $n=\frac{PV}{RT}$

By substituting the values, we get

$=\frac{1013250\times 1}{8.3145\times 298}$

$=408.94 \ moles$

As we know,

⇒ $Moles(n)=\frac{Mass(m)}{Molecular \ weight(MW)}$

or,

⇒ $MW=\frac{m}{n}$

$=\frac{11.5}{408.94}$

$=0.02812 \ Kg/mol$

$=28.12 \ g/mol$

3 0

2 years ago