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Crank
3 years ago
7

2LiClO+KHSO - Li2SO4 + Cl2 + KOOH

Chemistry
1 answer:
agasfer [191]3 years ago
4 0

Answer:

2.5 moles of KOOH are produced.

Explanation:

1)Given data:

Number of moles of KOOH produced = ?

Number of moles of LiClO = 5 mol

Solution:

Chemical equation:

2LiClO +  KHSO₄     →      Li₂SO₄ + Cl₂ + KOOH

now we will compare the moles of KOOH and LiClO.

                 LiClO          :          KOOH

                    2              :              1

                   5               :             1/2×5 = 2.5

2.5 moles of KOOH are produced.

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A mixture of helium, nitrogen, and oxygen has a total pressure of 752 mm Hg. The
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Answer: The partial pressure of oxygen in the mixture is 321 mm Hg

Explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

p_{total}=p_{He}+p_{N_2}+p_{O_2}

Given : p_{total} = total pressure of gases = 752 mm Hg

p_{He} = partial pressure of Helium = 234 mm Hg

p_{N_2} = partial pressure of nitrogen = 197 mm Hg

p_{O_2} = partial pressure of oxygen = ?

Putting in the values we get:

752mmHg=234mmHg+197mmHg+p_{O_2}

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3 years ago
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8.08 × 10⁻⁴

Explanation:

Let's consider the following reaction.

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The equilibrium concentration of Cl₂, x, is 0.0398 mol / 1.00 L = 0.0398 M.

The concentrations at equilibrium are:

[COCl₂] = 2.00 -x = 1.96 M

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The equilibrium constant (Keq) is:

Keq = [CO].[Cl₂]/[COCl₂]

Keq = (0.0398)²/1.96

Keq = 8.08 × 10⁻⁴

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vova2212 [387]
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Explanation-

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