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Crank
3 years ago
7

2LiClO+KHSO - Li2SO4 + Cl2 + KOOH

Chemistry
1 answer:
agasfer [191]3 years ago
4 0

Answer:

2.5 moles of KOOH are produced.

Explanation:

1)Given data:

Number of moles of KOOH produced = ?

Number of moles of LiClO = 5 mol

Solution:

Chemical equation:

2LiClO +  KHSO₄     →      Li₂SO₄ + Cl₂ + KOOH

now we will compare the moles of KOOH and LiClO.

                 LiClO          :          KOOH

                    2              :              1

                   5               :             1/2×5 = 2.5

2.5 moles of KOOH are produced.

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Explanation:

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The freezing point constant for benzene is 5.12 °C/m

Step 2: Calculate molality

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