Question

A sample of aluminum foil contains 7.90 x 10^23 atoms. What is the mass of the foil?

Answer 1

Answer:

35.3 g

Explanation:

Step 1: Given data

Number of atoms of aluminum: 7.90 × 10²³ atoms

Step 2: Calculate the number of moles corresponding to 7.90 × 10²³ atoms of aluminum

We will use Avogadro's number: there are 6.02 × 10²³ atoms of aluminum in 1 mole of atoms of aluminum.

7.90 × 10²³ atoms × (1 mol/6.02 × 10²³ atoms) = 1.31 mol

Step 3: Calculate the mass corresponding to 1.31 moles of aluminum

The molar mass of Al is 26.98 g/mol.

1.31 mol × 26.98 g/mol = 35.3 g