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3 years ago

5

TRUE OR FALSE Light can travel through materials that you cannot see through, like wood or aluminum foil.

1 answer:

Keith_Richards [23]3 years ago

8 0

i think its uhh......tralse

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Convert 60 kg to mg using the method of dimensional analysis

Svetradugi [14.3K]

600,000

PLEASE MARK AS BRAINLIEST ANSWER

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3 years ago

Which of the following is an engineering solution

Alona [7]

By "solution" it means a course of action that, once carried out, brings about some desired state of affairs. The use of engineer in this context is as a verb meaning "to arrange or bring about through skillful, artful contrivance."

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4 years ago

Read 2 more answers

When placed 1.18 m apart, the force each exerts on the other is 11.2 N and is repulsive. What is the charge on each

aleksandr82 [10.1K]

Answer:

$q=41.62\ \mu C$

Explanation:

Given that,

Force between two objects, F = 11.2 N

Distance between objects, d = 1.18 m

We need to find the charge on each objects. The force between charges is as follows :

$F=\dfrac{kq^2}{r^2}\\\\q=\sqrt{\dfrac{Fr^2}{k}} \\\\q=\sqrt{\dfrac{11.2\times (1.18)^2}{9\times 10^9}} \\\\q=41.62\ \mu C$

So, the charge on each sphere is $41.62\ \mu C$ .

7 0

3 years ago

Find the magnitude of the impulse delivered to a soccer ball when a player kicks it with a force of 1450 N . Assume that the pla

juin [17]

To solve this problem we will apply the concept of Impulse. Which is described as the product between the Force and the change in time. Mathematically this can be described as

$I = F \Delta t$

Where,

F = Force

$\Delta t$ = Time

Our values are given as,

F = 1450N

$\Delta t = 5.1*10^{-3} s$

Replacing we have,

$I = (1450)(5.1*10^{-3})$

$I = 7.395Kg\cdot m/s$

Therefore the impulse delivered to the soccer ball is $7.395Kg\cdot m/s$ or $7.395N\cdot s$

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3 years ago

A satellite is launched to orbit the Earth at an altitude of 2.90 x10^7 m for use in the Global Positioning System (GPS). Take t

marin [14]

Answer:

$T=66262.4s$

Explanation:

From the question we are told that:

Altitude $A=2.90 *10^7$

Mass $m=5.97 * 10^{24} kg$

Radius $r=6.38 *10^6 m.$

Generally the equation for Satellite Speed is mathematically given by

$V=(\frac{GM}{d} )^{0.5}$

$V=(\frac{6.67*10^{-11}*5.97 * 10^{24}}{6.38 *10^6+2.90 *10^7} )^{0.5}$

$V=3354.83m/s$

Therefore

Period T is Given as

$T=\frac{2 \pi *a}{V}$

$T=\frac{2 \pi *(6.38 *10^6+2.90 *10^7}{3354.83}$

$T=66262.4s$

4 0

3 years ago