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Liono4ka [1.6K]
3 years ago
8

Once a baseball has been hit into the air, what forces are acting upon it? How can you tell that any forces are acting upon the

ball?
Physics
1 answer:
Tom [10]3 years ago
8 0
Well, its in the air, so the air is "upon" the ball. and when it comes down...you catch it, and throw it, and get someone out, and win the game, and just keep doing that, and boooommm you're and pro baseball player. Life is good
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Which answer below is the formula mass of a water molecule
Firlakuza [10]
Molecular formula of water molecule is H₂O.
5 0
3 years ago
Which material is the best heat insulator?<br><br> metal<br><br> wood<br><br> plastic<br><br> glass
OlgaM077 [116]
Of the materials listed wood is the best insulator. It would be the least hot if exposed to similar temperatures.
5 0
3 years ago
Read 2 more answers
In a Broadway performance, an 84.5-kg actor swings from a R = 4.30-m-long cable that is horizontal when he starts. At the bottom
Arada [10]

Answer:

1.57772 m

Explanation:

M = Mass of actor = 84.5 kg

m = Mass of costar = 55 kg

v = Velocity of costar

V  = Velocity of actor

h_i = Intial height of actor = 4.3 m

g = Acceleration due to gravity = 9.81 m/s²

As the energy of the system is conserved

\frac{1}{2}MV^2=Mgh_i\\\Rightarrow V=\sqrt{2gh_i}\\\Rightarrow V=\sqrt{2\times 9.81\times 4.3}\\\Rightarrow V=9.18509\ m/s

As the linear momentum is conserved

MV=(m+M)v\\\Rightarrow v=\frac{MV}{m+M}\\\Rightarrow V=\frac{84.5\times 9.18509}{84.5+55}\\\Rightarrow v=5.56372\ m/s

Applying conservation of energy again

\frac{1}{2}(m+M)v^2=(m+M)gh_f\\\Rightarrow h_f=\frac{v^2}{2g}\\\Rightarrow h_f=\frac{5.56372^2}{2\times 9.81}\\\Rightarrow h_f=1.57772\ m

The maximum height they reach is 1.57772 m

3 0
3 years ago
6. A child tugs on a rope attached to a 0.62-kg toy with a horizontal force
ser-zykov [4K]

Answer:

Explanation:

Force Mass * acceleration

F = ma

a = F/m

Sum of force = 16.3N - 15.8N = 0.5N

Mass = 0.62kg

Substitute

a = 0.5/ * 0.62

a = 0.81m/s²

The acceleration of the toy is 0.81m/s²

8 0
3 years ago
A 10.0 kg weather rocket generates a thrust of 230 NN . The rocket, pointing upward, is clamped to the top of a vertical spring.
blondinia [14]

Answer: 0.2m

Explanation: Firstly only the Rocket's Weight Compress the spring which can be found by

F_r=M_r*g\\F_r=10*9.81\\F_r=98.1N

According to Hooks Law

F_r=k*x\\x=F_r/k\\x=98.1/480\\x=0.2m

The part b and c of this question is done in the attachment

7 0
3 years ago
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