1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Liono4ka [1.6K]
3 years ago
8

Once a baseball has been hit into the air, what forces are acting upon it? How can you tell that any forces are acting upon the

ball?
Physics
1 answer:
Tom [10]3 years ago
8 0
Well, its in the air, so the air is "upon" the ball. and when it comes down...you catch it, and throw it, and get someone out, and win the game, and just keep doing that, and boooommm you're and pro baseball player. Life is good
You might be interested in
According to the law of mass, 8 grams of hydrogen and 32 grams of oxygen will combine to form how many grams of water?
seropon [69]

Answer:

36 grams of water

Explanation:

mass of H2O = 0.5 x 18 = 9g

7 0
2 years ago
Which term refers to a variable that a scientist adjusts during an experiment
vladimir1956 [14]

Responding variable

Explanation:

7 0
3 years ago
Read 2 more answers
a 0.199 kg snowball moving west makes an inelastic collision with a 2.89 kg box moving 0.523 m/s west. afterward,they move west
kogti [31]

Answer:

The initial velocity of the snowball was 22.21 m/s

Explanation:

Since the collision is inelastic, only momentum is conserved. And since the snowball and the box move together after the collision, they have the same final velocity.

Let m_1 be the mass of the ball, and v_1 be its initial velocity; let m_2 be the mass of the box, and v_2 be its velocity; let v_f be the final velocity after the collision, then according to the law of conservation of momentum:

m_1v_1+m_2v_2=v_f(m_1+m_2).

From this we solve for v_1, the initial velocity of the snowball:

\boxed{v_1=\frac{v_f(m_1+m_2)-m_2v_2}{m_1}}

now we plug in the numerical values m_1=0.199\:kg, m_2=2.89\:kg, v_2=0.523\:m/s, and v_f=1.92\:m/s to get:

v_1=\frac{1.92*(0.199+2.89)-2.89*0.523}{0.199}

\boxed{v_1=22.21\:m/s}

The initial velocity of the snowball is 22.21 m/s.

<em>P.S: we did not take vectors into account because everything is moving in one direction—towards the west.</em>

4 0
3 years ago
Una persona cierra una puerta de 1 metro de ancho aplicando una fuerza de 40 [N], perpendicular a ella, a 90 [cm] de su eje de r
Damm [24]

Answer:

El módulo del torque aplicado es 36 Nm

Explanation:

En los movimientos rotatorios, la cantidad de fuerza aplicada no depende de la acción gravitacional sino del momento inercial, que es el equivalente angular de la inercia (masa) y representa la resistencia que un objeto ofrece al rotar alrededor de su eje. Cuando un cuerpo rígido rota alrededor de su eje debe considerarse , además de la masa, el radio de giro ya que estos dos factores determinan la resistencia del cuerpo a los cambios de movimiento rotatorio a través de un eje determinado.

De esta manera, se llama torque o momento de una fuerza a la capacidad de dicha fuerza para producir un giro o rotación alrededor de un punto.

En muchas ocasiones el punto de aplicación de la fuerza no coincide con el punto de aplicación en el cuerpo. En este caso la fuerza actúa sobre el objeto y su estructura a cierta distancia, mediante un  elemento que traslada esa acción de esta fuerza hasta el objeto. Entonces, el momento de una fuerza  es, matemáticamente,  igual al producto de la intensidad de la fuerza (módulo) por la distancia desde el punto de aplicación de la fuerza hasta el eje de giro:

M=F*d*sen θ

donde F es la fuerza en Newton (N), d la distancia en metros (m), θ el ángulo que forma la fuerza con el objeto al cual se le aplica la fuerza y M el momento, que se mide en Newton por metro (Nm).

En este caso:

  • F= 40 N
  • d= 90 cm= 0.9 m (siendo 100 cm= 1 m)
  • θ= 90° ya que la fuerza se aplica de forma perpendicular. Entonces sen θ= sen 90= 1

Reemplazando:

M=40 N*0.9 m* 1

Resolviendo:

M= 36 Nm

<u><em>El módulo del torque aplicado es 36 Nm</em></u>

3 0
2 years ago
Which has a higher frequency, a wave that makes 7 cycles per second or one that makes 12 cycles per second?
brilliants [131]

Answer:

A sound wave that has a higher frequency is a wave that makes 12 cycles per second.

Explanation:

The frequency of a wave is the same as the frequency of the vibrations that caused the wave. This takes more energy, so a higher-frequency wave has more energy than a lower-frequency wave with the same amplitude.

6 0
3 years ago
Other questions:
  • If a 10kg block is at rest on a table and a 1200N force is applied in the eastward direction for 10 seconds, what is the acceler
    11·1 answer
  • What type of circuit is illustrated?
    13·1 answer
  • 2. -/1 pointsSerPSE10 2.7.P.017.MI.
    12·1 answer
  • A friend asks you how much pressure is in your car tires. You know that the tire manufacturer recommends 30 psi, but it's been a
    9·1 answer
  • Under what condition will kinetic friction slow a sliding object?
    11·1 answer
  • A truck moves 30 km West, and then 40 km North, and then travels in a straight path back to its starting
    12·1 answer
  • Please can you help?? A skydiver is falling at terminal velocity when she opens her parachute. After a while she reaches a new t
    12·1 answer
  • H o m o zygous what does it mean
    8·1 answer
  • Metric conversions
    5·1 answer
  • How would the amount of potential energy stored in the bungee cord compare to
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!