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Liono4ka [1.6K]
3 years ago
8

Once a baseball has been hit into the air, what forces are acting upon it? How can you tell that any forces are acting upon the

ball?
Physics
1 answer:
Tom [10]3 years ago
8 0
Well, its in the air, so the air is "upon" the ball. and when it comes down...you catch it, and throw it, and get someone out, and win the game, and just keep doing that, and boooommm you're and pro baseball player. Life is good
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What do the arrows in food chains represent
OLga [1]
To represent in order how the animals

6 0
3 years ago
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if the net force of 15 N is exerted on an encyclopedia to cause it to accelerate at a rate of 5 m/s2. what is the mass of the en
Katarina [22]

Answer:

3 kg

Explanation:

F = ma

(15) = m(5)

m = 3 kg

3 0
3 years ago
How does the angle of incidence compare with the angle of reflection?​
S_A_V [24]

Answer:

The angle of incidence is the angle between this normal and the incident ray; the angle of reflection is the angle between this normal and the reflected ray. According to the law of reflection, the angle of incidence equals the angle of reflection.

Explanation:

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3 years ago
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How long does it take for a person that is walking at 2 meters per second to travel 1200 meters
Zanzabum

The time taken by a person that is walking at 2 meters per second to travel 1200 meters is 600 s

v = d / t

v = Velocity

d = Distance

t = Time

v = 2 m / s

d = 1200 m

t = d / v

t = 1200 / 2

t = 600 s

Velocity is the rate of change of distance with respect to time. It is denoted using V. Its unit is usually m / s.

Therefore, the time taken by thy person is 600 seconds

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5 0
1 year ago
If an airplane with a mass of 5 tons has gravitational potential energy of 1000 kilojoules, what is its height?
VLD [36.1K]
The gravitational potential energy of an object, measured with respect to the ground, is given by
U=mgh
where m is the object's mass, g is the gravitational acceleration and h is the height of the object measured from the ground.

In our problem, the mass of the plane is m= 5 tons = 5000 kg, while the potential energy is
U=1000 kJ=1 \cdot 10^6 J
so we can re-arrange the previous formula and use these data to calculate h, the height of the airplane:
h= \frac{U}{mg}= \frac{1 \cdot 10^6 J}{(5000 kg)(9.81 m/s^2)} =20.39 m
3 0
3 years ago
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