1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Liono4ka [1.6K]
3 years ago
8

Once a baseball has been hit into the air, what forces are acting upon it? How can you tell that any forces are acting upon the

ball?
Physics
1 answer:
Tom [10]3 years ago
8 0
Well, its in the air, so the air is "upon" the ball. and when it comes down...you catch it, and throw it, and get someone out, and win the game, and just keep doing that, and boooommm you're and pro baseball player. Life is good
You might be interested in
Parallel Plates Consider a very large conducting plate at potential V0 suspended a distance d above a very large grounded plane.
velikii [3]

Answer:

V = \frac{V_0x}{d}

Explanation:

Since the field lines are parallel and the electric field is uniform between two parallel plates, a test charge would experience the same force of attraction or repulsion no matter where it is located in the field,

I attached an image that could help to understand the representation of the field. The formula used to calculate it is given by,

E= -\frac{\Delta V}{x} (1)

If we want to consider the change in Voltage with respect to the position then it would be,

E= -\frac{dV}{dx}

According to the information provided, the potential is V_0 and there is a distance d, therefore

E= -\frac{V_0}{d} (2)

Taking equation (1) we can clear V, to what we have,

\frac{dV}{dx} = -E

dV = -Edx

Integrating,

V= - \int Edx

Substituting (2)

V = -\int \frac{V_0}{d} dx

V = \frac{V_0x}{d}

Where x is the height from the grounded plate.

8 0
3 years ago
You raise a bucket of water from the bottom of a deep well. if your power output is 138 w , and the mass of the bucket and the w
inn [45]
Maybe 34.5

I'm not quite sure

8 0
4 years ago
You drive a beat-up pickup truck along a straight road for 8.4 km at 70 km/h, at which point the truck runs out of gasoline and
Elan Coil [88]

Answer: a) 10.4km

b) 0.62h

C) 17km/h

d) 9.1km/h

Explanation:

A) suppose you move in the positive direction of an x axis, from a first position of x1 = 0 to a second position of x2 at the station. That second position must be at x2 = 8.4 km + 2.0 km = 10.4 km.

B) time interval Dtwlk (= 0.50 h), but we don't know the driving time interval Dt/dr. However, we know that for the drive the displacement Dx/dr is 8.4 km and the average velocity vavg,dr is 70 km/h.

This average velocity is the ratio of the displacement for the drive to the time interval for the drive:

dv = dx/ dt

dt = dx/dv = 8.4/70 = 0.12h

t = ti + two

t = 0.12 + 0.50 = 0.62h

C) avg speed for the entire trip is the ratio of the displacement of 10.4 km for the entire trip to the time interval of 0.62 h for the entire trip. 

Avg v = distance/time

10.4/0.62 = 16.8km/h

D) average speed is the ratio of the total distance you move to the total time interval you take to make that move. The total distance is 8.4 km + 2.0 km + 2.0 km = 12.4 km. The total time interval is 0.12 h + 0.50 h + 0.75 h = 1.37 h.

Avg speed = 12.4/1.37 = 9.1km/h

6 0
4 years ago
find the coefficient of kinetic friction for a 10 kg box being dragged steadily across the surface with a force of 2.0 Newtons​
Mazyrski [523]

Answer:

0.02

Explanation:

Force, F=\mu_k N where N is normal reaction and coefficient of kinetic friction is \mu_k. Also, N is equivalent to mg ie N=mg where m is mass of an object and g is acceleration due to gravity. Making \muthe subject of the formula then

\mu_k=\frac {F}{mg}

Substituting F with 2 N, m with 10 kg and g with 9.81 then

\mu_k=\frac {2}{10\times 9.81}=0.0203873598369\approx 0.02

5 0
4 years ago
A partially filled bag of cement with mass of 16 kg falls 40 m into a river from a bridge. What is its speed just before it hits
Verizon [17]

Answer:

28 metres

Explanation:

when the bag is about to hit the ground

potential energy = kinetic energy

mgh = \frac{1}{2}mv^{2}

where m = mass

g = acceleration due to gravity

v = speed

when you simplify the above equation and make v subject of the formular we have

v=\sqrt{2gh}

where g = 9.8m/s

h = 40

v=\sqrt{2\times 9.8\times 40}=28m

5 0
3 years ago
Other questions:
  • Given a 3.00 μF capacitor, a 7.75 μF capacitor, and a 5.00 V battery, find the charge on each capacitor if you connect them in t
    6·1 answer
  • A circuit with a resistance of 25 ohms is carrying a current of 2
    7·1 answer
  • After landing on a distant exoplanet as a member of the Space Force Spec Ops Team one of your first tasks is to measure the grav
    13·1 answer
  • Which is greater:a force of 10N or a force of 5 lbs?
    11·2 answers
  • An advertisement uses a movie star holding a bottle of perfume. This ad is an example of which of the following?
    12·1 answer
  • The maximum Compton shift in wavelength occurs when a photon isscattered through 180^\circ .
    10·1 answer
  • The volume V of a right circular cylinder of radius r and height h is V=πr2h. (a) How is dVdt related to drdt if h is constant a
    12·1 answer
  • How many total atoms are in the following: 3NHe4<br> A.15<br> B.3<br> C.7<br> D.12
    5·2 answers
  • Sarah rides her horse with a constant speed of 12km/h. How far can she travel in 3 hours?
    12·1 answer
  • A model shows a machine that works using electric fields. What would this machine need for the electrical field to function prop
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!