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Mazyrski [523]
3 years ago
8

If a boat and its riders have a mass of 1100 kg and the boat drifts in at 1.3 m/s how much work does Sam do to stop it

Physics
1 answer:
andriy [413]3 years ago
5 0

Answer:

-929.5Joules

Explanation:

To get the work done by sam, we will calculate the kinetic energy of sam expressed as;

KE = 1/2mv²

m is the mass = 1100kg

v is the velocity = 1.3m/s

KE = 1/2(1100)(1.3)²

KE = 550(1.69)

KE = 929.5Joules

Since Sam is opposing the direction of movement, work done by him will be a negative work i.e -929.5Joules

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The frequency of a person's pendulum is 0.3204 Hz when at a location where g is known to be exactly 9.800 m/s^2.
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Answer:

A) g = 9.751 m/s², B)       h = 2.573 10⁴ m

Explanation:

The angular velocity of a pendulum is

           w = √ g / L

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          w = 2π f

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A) with the initial data we can look for the pendulum length

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        g = 4π² f²  L

        g = 4π² 0.3196²  2.4181

        g = 9.75096 m / s²

         g = 9.751 m/s²

B) The value of the acceleration of gravity can be found with the law of universal gravitation

           F = G m M / R_{e}²

And Newton's second law

           W = m g

           W = F

         G m M / R_{e}² = mg

         g = G M / R_{e}²

         R_{e}² = G M / g

Let's calculate

          R_{e}² = 6.67 10⁻¹¹ 5.98 10²⁴ /9.75096

          R = √ 4.0905 10¹³ = √ 40.9053 10¹²

          R = 6.395726 10⁶ m

The height above sea level is

         h = R - [tex]R_{e}[/tex

         h = (6.395726 -6.37) 10⁶

         h = 0.0257256 106

         h = 2.573 10⁴ m

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Learn more about speed of sound:brainly.com/question/15137350

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