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kykrilka [37]
3 years ago
11

Suppose two loaded train cars are moving toward one another, the first having a mass of 1.50 \times 10^5\, \mathrm{kg}1.50×10 5

kg and a velocity of (0.11 \, \mathrm{m/s})\, \hat{i}(0.11m/s) i ^ , and the second having a mass of 1.10 \times 10^5\, \mathrm{kg}1.10×10 5 kg and a velocity of (-0.21 \, \mathrm{m/s})\, \hat{i}(−0.21m/s) i ^ . What is their final velocity?
Physics
1 answer:
lara31 [8.8K]3 years ago
6 0

Answer:

0.2358

Explanation:

We need here  apply the law momentum conservation, for objects who collide.

The equation is given by,

m_1v_1+m_2v_2= (m_1+m_2)v_f

Our values are giving by,

m_1=1.5*10^5Kg\\v_2=0.11m/s\\m_2=1.1*10^5Kg\\v_2=-0.21m/s

We replace in our equation and solve for V_f, then

(1.5*10^5)(0.11)+(1.1*10^5)(-0.21)=(1.5*10^5+1.1*10^5)v_f

-6600=260000v_f

v_f=-\frac{6600}{260000}

v_f=-0.2538m/s

Therefore their final velocity is -0.2358m/s (Negative symbol only indicate change in the direction)

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wlad13 [49]

The force between them <em>decreases</em><em>,</em> as the square of the distance.

For example ...

-- If you move them apart to double the original distance, the force becomes (1/2²) = 1/4 of the original force.

-- If you move them apart to 3 times the original distance, the force becomes (1/3²) = 1/9 of the original force.

-- If you move them apart to 5 times the original distance, the force becomes  (1/5²) = 1/25 of the original force.

(Gravity works exactly the same way.)

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2 years ago
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tensa zangetsu [6.8K]
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Magnetic domain is defined as a group of atoms with magnetic fields.

A piece of iron can only become a magnet when the magnetic domain aligns.

Since we have an unmagnetized piece of iron, this means that its domain is not aligned. However, this does not mean that the domain does not exist.

Based on the above, the best choice would be:
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Hope this helps :)
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3 years ago
An apple falls off a roof .It takes the apple 15.7 seconds to hit the floor . How far did the apple fall?
slava [35]

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3 years ago
What average net force is required to stop a 1950 kg car in 10.5 s if it’s initially traveling at 28m/s
nika2105 [10]

Answer:

<em>An average net force of 5200 N is needed to stop the car</em>

Explanation:

<u>Cinematics and Dynamics</u>

Cinematics describes the variables involved in the movement without dealing with its causes. There are four main concepts in cinematics: Velocity (or its scalar equivalent, the speed), acceleration, time, and displacement (or the scalar equivalent, distance).

The acceleration can be calculated by:

\displaystyle a=\frac{v_f-v_o}{t}

The initial speed is vo=28 m/s, it stops (vf=0) in t=10.5 seconds, thus the acceleration is:

\displaystyle a=\frac{0-28}{10.5}

a = -2.67~m/s^2

The acceleration is negative because the car loses speed.

Knowing the mass of the car m=1950 Kg, we can calculate the net force required to stop the car by using the formula:

F = m.a =1950*2.67

F = 5200 N

An average net force of 5200 N is needed to stop the car

7 0
2 years ago
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