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kykrilka [37]
3 years ago
11

Suppose two loaded train cars are moving toward one another, the first having a mass of 1.50 \times 10^5\, \mathrm{kg}1.50×10 5

kg and a velocity of (0.11 \, \mathrm{m/s})\, \hat{i}(0.11m/s) i ^ , and the second having a mass of 1.10 \times 10^5\, \mathrm{kg}1.10×10 5 kg and a velocity of (-0.21 \, \mathrm{m/s})\, \hat{i}(−0.21m/s) i ^ . What is their final velocity?
Physics
1 answer:
lara31 [8.8K]3 years ago
6 0

Answer:

0.2358

Explanation:

We need here  apply the law momentum conservation, for objects who collide.

The equation is given by,

m_1v_1+m_2v_2= (m_1+m_2)v_f

Our values are giving by,

m_1=1.5*10^5Kg\\v_2=0.11m/s\\m_2=1.1*10^5Kg\\v_2=-0.21m/s

We replace in our equation and solve for V_f, then

(1.5*10^5)(0.11)+(1.1*10^5)(-0.21)=(1.5*10^5+1.1*10^5)v_f

-6600=260000v_f

v_f=-\frac{6600}{260000}

v_f=-0.2538m/s

Therefore their final velocity is -0.2358m/s (Negative symbol only indicate change in the direction)

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