The momentum of the ball when it hits the ground is 4.89 kg.m/s.
The given parameters;
- <em>mass of the baseball, m = 0.145 kg</em>
- <em>height of fall of the ball, h = 58 m</em>
The final velocity of the ball when it hits the ground is calculated as follows;
The momentum of the ball when it hits the ground is calculated as follows;
P = mv
P = 0.145 x 33.72
P = 4.89 kg.m/s
Thus, the momentum of the ball when it hits the ground is 4.89 kg.m/s.
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Answer:
Explanation:
t = Time taken = 0.46
u = Initial velocity
v = Final velocity
s = Displacement = 1 m
a = Acceleration
The acceleration due to gravity is 9.45179 m/s²
The function is
Answer:
2.43J
Explanation:
Given parameters:
Mass of the arrow = 0.155kg
Velocity = 31.4m /s
Unknown:
Kinetic energy when it leaves the bow = ?
Solution:
The kinetic energy of a body is the energy in motion of the body;
it can be derived using the expression below:
K.E = 
m v²
m is the mass
v is the velocity
Solve for K.E;
K.E = x 0.155 x 31.4 = 2.43J
The initial position of the object was found to be 134.09 m.
<u>Explanation:</u>
As displacement is the measure of difference between the final and initial points. In other words, we can say that displacement can be termed as the change in the position of the object irrespective of the path followed by the object to change the path. So
Displacement = Final position - Initial position.
As the final position is stated as -55.25 meters and the displacement is also stated as -189.34 meters. So the initial position will be
Initial position of the object = Final position-Displacement
Initial position = -55.25 m - (-189.34 m) = -55.25 m + 189.34 m = 134.09 m.
Thus, the initial position for the object having a displacement of -189.34 m is determined as 134.09 m.
