Decomposition is a part of the carbon cycle that occurs slowly hence movement of carbon dioxide into the atmosphere when bacteria decomposes dead matter is a slow part of the carbon cycle.
<h3>What is the carbon cycle?</h3>
The carbon cycle is part of the biogeochemical cycles that exist in nature. It refers to the movement of carbon in the ecosystem. The carbon cycle cuts across the air, the land and the water bodies.
The process in the carbon cycle that occurs slowly among the options is the movement of carbon dioxide into the atmosphere when bacteria decomposes dead matter.
Learn more about carbon cycle: brainly.com/question/1627609
<span> mass of glucose = 0.055 *165 = 9.075 g
vol of methyl alc = 0.185 * 1.87 = 0.346 L = 346 ml
% NaCl ( m/v ) = mass NaCl * 100/ vol of soln
or Vol of Soln = mass NaCl / % NaCl (m/v)
= 32.1 * 100 / 6 = 535 ml the total vol of soln</span>
Answer:
lymphocytes
Explanation:
it consists of the b and the t cells
First we have to find Ka1 and Ka2
pKa1 = - log Ka1 so Ka1 = 0.059
pKa2 = - log Ka2 so Ka2 = 6.46 x 10⁻⁵
Looking at the values of equilibrium constants we can see that the first one is really big compared to second one. so, the pH will be affected mainly by the first ionization of the acid.
Oxalic acid is H₂C₂O₄
H₂C₂O₄ ⇄ H⁺ + HC₂O₄⁻
0.0356 M 0 0
0.0356 - x x x
Ka1 =
![\frac{[H^+][HC2O4^-]}{[H2C2O4]}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5BH%5E%2B%5D%5BHC2O4%5E-%5D%7D%7B%5BH2C2O4%5D%7D%20)
= x² / 0.0356 - x
x = 0.025 M
pH = - log [H⁺] = - log (0.025) = 1.6