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valina [46]
3 years ago
14

How does the diameter of an atom compare with the diameter of the nucleus

Chemistry
1 answer:
const2013 [10]3 years ago
4 0
Well a nucleus is in an atom so I'm guessing you mean include the energy levels and I will answer it depends on how many energy levels it has.
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What element is being oxidized in the following redox reaction? Pb 2+(aq) + NH4 +(aq) - Pb(s) + NO3 (aq)
castortr0y [4]
The answer for your question is c.
5 0
3 years ago
Is an example of the carbon cycle occurring slowly?(1 point)
o-na [289]

Decomposition is a part of the carbon cycle that occurs slowly hence  movement of carbon dioxide into the atmosphere when bacteria decomposes dead matter is a slow part of the carbon cycle.

<h3>What is the carbon cycle?</h3>

The carbon cycle is part of the biogeochemical cycles that exist in nature. It refers to the movement of carbon in the ecosystem. The carbon cycle cuts across the air, the land and the water bodies.

The process in the carbon cycle that occurs slowly among the options is the movement of carbon dioxide into the atmosphere when bacteria decomposes dead matter.

Learn more about carbon cycle: brainly.com/question/1627609

7 0
2 years ago
How many grams (m) of glucose are in 165 ml of a 5.50% (m/v) glucose solution? express your answer numerically in grams?
Leya [2.2K]
     <span> mass of glucose = 0.055 *165 = 9.075 g

vol of methyl alc = 0.185 * 1.87 = 0.346 L = 346 ml

% NaCl ( m/v ) = mass NaCl * 100/ vol of soln

or Vol of Soln = mass NaCl / % NaCl (m/v)

= 32.1 * 100 / 6 = 535 ml the total vol of soln</span>
6 0
3 years ago
The blood cells that directly attack germs are: *​
irga5000 [103]

Answer:

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4 0
3 years ago
Read 2 more answers
The leaves of the rhubarb plant contain high concentrations of diprotic oxalic acid (hooccooh) and must be removed before the st
Andrei [34K]
First we have to find Ka1 and Ka2
pKa1 = - log Ka1 so Ka1 = 0.059
pKa2 = - log Ka2  so Ka2 = 6.46 x 10⁻⁵
Looking at the values of equilibrium constants we can see that the first one is really big compared to second one. so, the pH will be affected mainly by the first ionization of the acid.
Oxalic acid is H₂C₂O₄
H₂C₂O₄      ⇄     H⁺   + HC₂O₄⁻
0.0356 M            0          0
0.0356 - x            x          x
Ka1 = \frac{[H^+][HC2O4^-]}{[H2C2O4]} = x² / 0.0356 - x
x = 0.025 M
pH = - log [H⁺] = - log (0.025) = 1.6
5 0
3 years ago
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