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forsale [732]
3 years ago
7

Which is most responsible for the uneven heating of the air in the atmosphere

Chemistry
2 answers:
Diano4ka-milaya [45]3 years ago
5 0
That would be convection. This is a test. ;)
VLD [36.1K]3 years ago
5 0
Convection currents
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If your good at science you could help me out so much!
Andrei [34K]

Answer:

Potassium (K) and Lithium (Li) for the fist one i cant see the second

Explanation:

6 0
2 years ago
QUICK (lots of points) How many lone pairs are present in Xylene?!
Snezhnost [94]

i dont think their are a exact number

7 0
3 years ago
Read 2 more answers
Calculate the period when the frequency is 50Hz.​
liraira [26]

Answer:

For example, a wave with a time period of 2 seconds has a frequency of 1 ÷ 2 = 0.5 Hz. A radio wave has a time period of 0.0000003333333 seconds.

8 0
2 years ago
What is the amount of solute required if the solution is 50 ml and the solvent is 35 ml. Solve and explain
e-lub [12.9K]

Answer:

15 mL of the solute

Explanation:

From the question given above, the following data were obtained:

Solution = 50 mL

Solvent = 35 mL

Solute =?

Solution is simply defined as:

Solution = solute + solvent

With the above formula, we can easily obtain the solute in the solution as follow:

Solution = 50 mL

Solvent = 35 mL

Solute =?

Solution = solute + solvent.

50 = solute + 35

Collect like terms

50 – 35 = solute

15 = solute

Solute = 15 mL

Therefore, 15 mL of the solute is required.

3 0
3 years ago
Complete the reaction, which is part of the electron transport chain. The abbreviation FMN represents flavin mononucleotide. Use
Margarita [4]

Answer:

1. NADH + H⁺ + FMN + Q ⟶ NAD⁺ + FMN + QH₂

2. The reactant that is reduced is Q

3. The charge on iron on the right side is +2, Fe²⁺

Explanation:

NADH + H⁺ + FMN + Q ⟶ NAD⁺ + FMN + QH₂

The reaction above is catalysed by NADH:ubiquinone oxidoreductase (complex 1), which transfers a hydride ion from NADH to FMN, from which two electrons pass through a series of of Fe-S centers to the iron-sulfur protein N-2. Electron transfer from N-2 to Ubiquinone forms QH₂

The species in a reaction which gains hydrogen irons is reduced,   Therefore, the reactant that is reduced is Q, ubiquinone to form QH₂, ubiquinol.

To determine the oxidation number of iron on the right side of the reaction below,

QH2 + 2cyt c ( Fe3+) ⟶ Q + 2cyt c(Fex) + 2H^+

Sum of charges on the left side = Sum of charges on the right side

Sum of charges on the left side = 2 *+3 = +6

Therefore 2 * x + 2= 6

2x = 6 -2 = 4

x = 4/

x = 2

Therefore the charge on iron on the right side is +2, Fe²⁺

4 0
3 years ago
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