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Natasha_Volkova [10]
3 years ago
7

What color did you observing of marker?not color its a pure of in​

Chemistry
1 answer:
Gekata [30.6K]3 years ago
7 0
Blue and purple and red
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Calculate the molar mass of naoh and the mass of solid naoh needed to prepare 250 ml of 0.1 m naoh solution
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In ionic bond formation, the lattice energy of ions ________ as the magnitude of the ion charges _______ and the radii ________.
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4 years ago
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Using the following balanced chemical equation 8 H2 + S8à 8 H2S. Determine the mass of the product (molar mass = 34.08g/mol) if
Karolina [17]

Answer: 7.29 g of H_2S will be produced from the given masses of both reactants.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

{\text{Moles of} H_2}=\frac{1.35g}{2.01g/mol}=0.672moles

\text{Moles of} S_8=\frac{6.86g}{256.5g/mol}=0.0267moles

8H_2+S_8\rightarrow 8H_2S

According to stoichiometry :

1 mole of S_8 require = 8 moles of H_2

Thus 0.0267 moles of S_8 will require=\frac{8}{1}\times 0.0267=0.214moles  of H_2

Thus S_8 is the limiting reagent as it limits the formation of product and H_2 is the excess reagent.

As 1 mole of S_8 give = 8 moles of H_2S

Thus 0.0267 moles of S_8 give =\frac{8}{1}\times 0.0267=0.214moles  of H_2S

Mass of H_2S=moles\times {\text {Molar mass}}=0.214moles\times 34.08g/mol=7.29g

Thus 7.29 g of H_2S will be produced from the given masses of both reactants.

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4 years ago
How will the vapor pressure of an aqueous solution of sodium chloride compare to that of pure water?
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The solutions vapor pressure would be lower.
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