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ICE Princess25 [194]
3 years ago
8

A plane is moving due north, directly towards its destination. Its airspeed is 200 mph. A constant breeze is blowing from west t

o east at 60 mph. At what rate is the plane moving north?
Physics
1 answer:
Vikki [24]3 years ago
4 0

Answer:

200 m/s

Explanation:

Given that,

A plane is moving due north, directly towards its destination. Its airspeed is 200 mph. A constant breeze is blowing from west to east at 60 mph.

We need to find the rate at which the plane is moving towards North. It can be given by :

V_x=v\cos\theta

Where

\theta is the angle with the North

V_x=200\times \cos(\dfrac{60}{200})\\\\=199.99\ m/s\\\\\approx 200\ m/s

Hence, the plane is moving at a rate of 200 m/s.

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What does the word apparent mean in apparent visual magnitude
SSSSS [86.1K]

The word 'apparent' mean in apparent visual magnitude is, how bright the star appears when viewed from Earth.

What is visual magnitude?

The brightness of a celestial body is determined by eye estimation with or without optical aid or by other instrumentation equivalent to the eye in spectral sensitivity.

Apparent magnitude:

  • Apparent magnitude is a measure of how bright the star appears when viewed from Earth.
  • It is a measure of the brightness of a star or other astronomical object observed from Earth.
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Hence,

The word 'apparent' mean in apparent visual magnitude is, how bright the star appears when viewed from Earth.

Learn more about visual magnitude here:

<u>brainly.com/question/14782876</u>

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2 years ago
Which force is responsible for the formation of waves? A. gravity B. wind C. friction D. centripetal
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Gravity is the cause of formation waves.
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3 years ago
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A cart moves along a track at a velocity of 3.5 cm/s. When a force is applied to the cart, its velocity increases to 8.2 cm/s. I
Lorico [155]

Answer:

3.13cm/s²

Explanation:

Given

Initial velocity u = 3.5cm/s

Final velocity v = 8.2cm/s

Time t = 1.5secs

Required

Acceleration of the cart a

To get that, we will use the equation of motion

v = u+at

Substitute the given parameters

8.2 = 3.5+1.5a

1.5a = 8.2-3.5

1.5a = 4.7

a = 4.7/1.5

a = 3.13cm/s²

Hence the acceleration to the cart is 3.13cm/s²

3 0
3 years ago
What is the change in electric potential energy in moving an electron from a location 3 × 10-10 m from a proton to a location 7
joja [24]

Answer:

4.39 x 10^-19 J

Explanation:

q1 = 1.6 x 10^-19 C

q2 = - 1.6 x 10^-19 C

r1 = 3 x 10^-10 m

r2 = 7 x 10^-10 m

The formula for the potential energy is given by

U1 = k q1 q2 / r1 = - (9 x 10^9 x 1.6 x 10^-19 x 1.6 x 10^-19) / (3 x 10^-10)

U1 = - 7.68 x 10^-19 J

U2 = k q1 q2 / r2 = - (9 x 10^9 x 1.6 x 10^-19 x 1.6 x 10^-19) / (7 x 10^-10)

U2 = - 3.29 x 10^-19 J

Change in potential energy is

U2 - U1 = - 3.29 x 10^-19 + 7.68 x 10^-19 = 4.39 x 10^-19 J

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4 years ago
assume that in an unpolished floor a lady us pushing a 40 kg box to the left with an applied force of 192 N. find the sum of for
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