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Novay_Z [31]
3 years ago
15

5. Solve for x.

Mathematics
1 answer:
exis [7]3 years ago
4 0

Answer:

12*56-56+11=12

Step-by-step explanation:

12 for 56

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Can you answer this
Burka [1]
Answer is 2x^+3x-3 with reminder 4
6 0
3 years ago
A first number plus twice a second number is 13. Twice the first number plus the second totals 14. find the numbers​
sashaice [31]

Answer:

the first number is 5 the second number is 4

Step-by-step explanation:

first number = x

second number = y

X+2y=13 given this isolate x  x = 13-2y

2x+y=14 substitute 13-2y for x

2(13-2y)+y=14

26-4y+y=14

-3y=-12

y=4 taking this number substitute into either equation above

x+2(4)=13

x+8=13

x=5

4 0
3 years ago
4x^2-7x=15<br> Solve by factoring and please please please explain or show the work
vodomira [7]

Answer:

x=3 and x=-1.25

Step-by-step explanation:

4x^2-7x=15

subtract 15 from each side:

4x^2-7x-15=0

factor  (trying different numbers that the sum is 7 and the quotient is 15)

(2x-6 )(2x+2.5 )=0

2x-6=0 add 6 to each side

2x=6

x=3

2x+2.5=0   subtract 2.5 from each side

2x=-2.5

x=-1.25

8 0
3 years ago
Find the zeros of y = x + 6x- 4 by completing the square.
dsp73

Answer:

\large\boxed{x=-3\pm\sqrt{13}}

Step-by-step explanation:

(a+b)^2=a^2+2ab+b^2\qquad(*)\\\\\\x^2+6x-4=0\qquad\text{add 4 to both sides}\\\\x^2+2(x)(3)=4\qquad\text{add}\ 3^2=9\ \text{to both sides}\\\\\underbrace{x^2+2(x)(3)+3^2}_{(*)}=4+9\\\\(x+3)^2=13\Rightarrow x+3=\pm\sqrt{13}\qquad\text{subtract 3 from both sides}\\\\x=-3\pm\sqrt{13}

8 0
3 years ago
HELP PLEASE!!!!
mina [271]

Answer:


Step-by-step explanation:

1) Write 8x+14 as 2(4x+7) and now multiply by 1/2 so that we get 4x+7

2)Subtract 7 from both sides

4x+7=39

-7       -7

4x=32

3) Divide by 8

x=8

Thus we get x=8 as answer

So reasons are

i) Distributive property

ii) Subtraction property of equality

iii) Division property of equality

6 0
3 years ago
Read 2 more answers
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