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alekssr [168]
3 years ago
11

4 is what percent of 20

Mathematics
1 answer:
neonofarm [45]3 years ago
3 0
20%
Finding percentage u have to
Divide 4/20= 0.2 then multiply by 100 to get percentage which is 20%
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The heights in inches, of some small trees for sale at a garden store are 62, 62, 59, 61, 59, 70, 59, and 62. What is the median
Nana76 [90]

Answer:

Step-by-step explanation:

the mean height, remember is the average

62+62+59+61+59+70+59+62=494/8=61.75

median is the middle value, so we will write the numbers in order

59,59,59,61,62,62,62,70

we have an even number so we add the middle numbers and divide by 2,

the median=61+62=123/2=61.50  

mode is the number that occurs most often : 62 and 59

5 0
3 years ago
9. Given f(x) = 7x2 and g(x) = x +1,<br> find f(g(x)). SHOW ALL WORK.
Nezavi [6.7K]

I hope this helps you

f(g(x)) =f(x+1)=7(x+1)^2

f(x+1)=7.(x^2+2x+1)

f(x+1)=7x^2+14x+7

8 0
3 years ago
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Is the binomial a factor of the polynomial nominal function?
Sedbober [7]

The factors for given equation f(x)=x^{3} +3x^{2} -25x-75.

  • (x-1) - No
  • (x-3) - No
  • (x+3) - Yes
  • (x-5) - Yes
  • (x+5) - Yes

<u>Step-by-step explanation:</u>

The given equation is f(x)=x^{3} +3x^{2} -25x-75 .

Add 0 at the end of the equation.

x^{3} +3x^{2} -25x-75 = 0.

Let us group the given equation,

(x^{3} +3x^{2}) -(25x-75) =0.

⇒ Group 1: x^{3} +3x^{2} .

Group 2: - 25x +75 .

Pull out factor from each group,

⇒ Group 1: (x+3)(x^{2}).

Group 2: (x+3) (-25).

Join the two group since both (x+3) is common in both groups.

(x+3)(x^{2} -25) =0.

One of the factor is (x+3).

Other factors are solved by the formula, a^{2}-b^{2} = (a+b) (a-b) .

(x+3)(x^{2} -25) = (x+5) (x-5) .

The other factors are (x+5) and (x-5).

7 0
3 years ago
What is an hypothesis?
vova2212 [387]

Answer: A hypothesis is like a prediction

Hope it helps

3 0
3 years ago
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Work out the circumference of this circle.<br> Give your answer in terms of 3.142<br> r=6 mm
soldi70 [24.7K]

Answer:

C≈37.7

Step-by-step explanation:

C=2πr=2·π·6≈37.69911

<h3><em>i rounded</em></h3><h3><em /></h3>
6 0
3 years ago
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